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Serggg [28]
3 years ago
6

A truck can be rented from Company A form ​$130 a day plus $0.30 per mile. Company B charges ​$50 a day plus $0.80 per mile to r

ent the same truck. Find the number of miles in a day at which the rental costs for Company A and Company B are the same.
Mathematics
1 answer:
navik [9.2K]3 years ago
4 0

Answer:

160 miles

Step-by-step explanation:

Company A form ​$130 a day plus $0.30 per mile

Company A = 130 + 0.30x

Company B charges ​$50 a day plus $0.80 per mile

Company B = 50 + 0.80x

Where,

x = number of miles

Equate the cost of company A and company B

130 + 0.30x = 50 + 0.80x

Collect like terms

130 - 50 = 0.80x - 0.30x

80 = 0.50x

Divide both sides by 0.50x

x = 80 / 0.50

= 160

x = 160 miles

The number of miles in a day at which the rental costs for Company A and Company B are the same is 160 miles

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IRINA_888 [86]

ANSWER

45.6cm to the nearest tenth.

EXPLANATION

The diagonal of the rectangular painting is 62cm.

The height of the painting is 42 cm.

The height of the painting h , the diagonal, and the width of the painting forms a right triangle with the diagonal being the hypotenuse.

From the Pythagoras Theorem,

{w}^{2}  +  {42}^{2}  = {62}^{2}

{w}^{2} = {62}^{2} -  {42}^{2}

{w}^{2}  = 2080

{w} =  \sqrt{2080}

w = 4 \sqrt{130}

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Answer:

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