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Serggg [28]
2 years ago
6

A truck can be rented from Company A form ​$130 a day plus $0.30 per mile. Company B charges ​$50 a day plus $0.80 per mile to r

ent the same truck. Find the number of miles in a day at which the rental costs for Company A and Company B are the same.
Mathematics
1 answer:
navik [9.2K]2 years ago
4 0

Answer:

160 miles

Step-by-step explanation:

Company A form ​$130 a day plus $0.30 per mile

Company A = 130 + 0.30x

Company B charges ​$50 a day plus $0.80 per mile

Company B = 50 + 0.80x

Where,

x = number of miles

Equate the cost of company A and company B

130 + 0.30x = 50 + 0.80x

Collect like terms

130 - 50 = 0.80x - 0.30x

80 = 0.50x

Divide both sides by 0.50x

x = 80 / 0.50

= 160

x = 160 miles

The number of miles in a day at which the rental costs for Company A and Company B are the same is 160 miles

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Arte-miy333 [17]

Answer:

-16

Step-by-step explanation:

Represent the number by n.

Then:

8(n + 18) = 16

Performing the indicated multiplication, we get:

8n + 144 = 16

Subtracting 144 from both sides results in 8n = -128.

Dividing both sides by 8:  n = -128/8  =  -16

The number was -16.

4 0
3 years ago
How many solutions to y=2x-3 y=-x+3
Ivan

Answer:

y = 1

Step-by-step explanation:

I dunno what you need but that's the answer to y...

8 0
3 years ago
Read 2 more answers
Find the area and perimeter of the room.. the vertices are 10,20 -10,20 -10,-10 10,-10
Ierofanga [76]
The numbers in this problem are ordered pairs, which are points on a graph.
These are (10, 20), (-10, 20), (-10, -10), and (10, -10).
To find the area and perimeter of this shape, you must first find the distance between each point.

Distance between (10, 20) and (-10, 20):
Since the y-value remains the same here, we just have to find the difference in x-values.
This means 10 - (-10)
A negative being subtracted is the same as a positive being added.
That means 10 - (-10) is the same as 10 + 10.
10 + 10 = 20, so the distance between (10, 20) and (-10, 20) is 20 units.

Distance between (-10, 20) and (-10, -10):
The x-values are the same here so just find the difference between the y-values.
20 - (-10) = 20 + 10 = 30
The distance between the (-10, 20) and (-10, -10) is 30 units.

Distance between (-10, -10) and (10, -10):
The y-values are the same so just find the difference between the x-values.
10 - (-10) = 10 + 10 = 20
The distance between (-10, -10) and (10, -10) is 20 units.

Distance between (10, -10) and (10, 20):
The x-values are the same so find the difference between the y-values.
20 - (-10) = 20 + 10 = 30
The distance between (10, -10) and (10, 20) is 30 units.

So now we know the side lengths of the room are 20 units, 30 units, 20 units, and 30 units.

To find the perimeter, add all the side lengths together.
20 + 30 + 20 + 30 = 100
The perimeter of the room is 100 units.

To find the area, multiply the length by the width.
The length is 20 units and the width is 30 units.
20 • 30 = 600
The area of the room is 600 units.

Final answers:
Perimeter = 100
Area = 600

Hope this helps!
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2 years ago
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tigry1 [53]

Answer:

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mote1985 [20]
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