1) y=(7/2)x-2.
Slope is the coefficient of x, that is 7/2
Intercept x is the value of x when y = 0 ==> 0=(7/2) X - 2==> 7/2x=2 &x=4/7
so intercept x, (4/7,0)
Intercept y is the value of y when x=0 ==> y= (7/2).(0) - 2 ==> y = 2
and so intercept y, (0,-2)
Now you will follow the same logic to find the are same questions
2) y= -6x + 3 ==>Slope= -6, Intercept x =1/2 & intercept y=3
3) y=-5 has a slope 0 (it doesn't exist). The graph is a line // to x-axis at y=-5
4)y=(6/5)x + 1:==>Slope= -5/6, Intercept x =-5/6 & intercept y=1
5) y=(1/4)x + 2 ==>Slope= 1/4, Intercept x =-8 & intercept y=2
6) x=5, this ligne is // to y axis at x=-5
Answer:
m∠5 = 44°; m∠7 = 44°
Step-by-step explanation:
Angle 4 and 1 are supplementary (they make up a line) and their sum is equal to 180 degrees.
Subtracting the measure of angle 4 from 180 degrees gives the measure of angle 1. (180 - 136 = 44).
So Angle 1's measure is 44 degrees.
According to the Corresponding Angle Postulate, Angle 1 and Angle 5 are congruent. Therefore, m∠5 = 44°
According to the Vertical Angles Postulate (if two angles are vertical, they are congruent), ∠5 ≅ ∠7, meaning that m∠5 = m∠7.
So m∠7 = 44°
Answer:
the axis of symmetry is X = 1
Step-by-step explanation:
make sure to ask if you need any further guidance.
