Given that question: Shyam invested money in the stock market. In the first
year, his stock increased 20%. He paid his stock broker $300 and then lost
$450. He withdrew $500, and then his remaining investment doubled. Shyam’s investment is now worth $7100. How much was Shyam’s original investment?
The solution is as follows:
Let the amount Shyam invested in the stock market be x, then in the first year his stock increased by 20% giving 1.2x.
He paid his stockbrocker $300 to have 1.2x - $300 left, and he lost $450 to have 1.2x - $300 - $450 = 1.2x - $750 left.
He withdrew $500 to have 1.2x - $750 - $500 = 1.2x - $1,250 left.
His remaining investment doubled to have 2(1.2x - $1,250) = 2.4x - $2,500
Shyam's investment is now worth $7,100 which means that
2.4x - $2,500 = $7,100
2.4x = $7,100 + $2,500 = $9,600
x = $9,600 / 2.4 = $4,000
Therefore, the value of Shyam's original investment is $4,000
Step-by-step explanation:
Let's start with solving for line L using slope-intercept form (y=mx+b)
We can see that the y-intercept is 4, and the slope is rise/run. From point (5,2) to (0,5), the rise is 2, and the run is -5 (it goes backwards 5).
Using this, we can form our equation for Line L: y = -2/5x + 4
Now let's solve for Line M.
There is something very important to notice before we jump into this. Both of these lines (Line L and M) are parallel (they never touch) and therefore will contain the same slope as each other (-2/5). The y-intercept for this equation we can see is -1, as the line touches (0,-1). Now lets form our equation;
Line M: y = -2/5+4
Solving a system of equation means to find two (or more) line's interceptions on a graph (where they meet/touch). Because both of these lines are parallel and never touch each other, there is no definite answer. Therefore our answer is No Solutions.
Answer:
this is hard sorry
Step-by-step explanation:
<u>Answer:</u>
The basic identity used is .
<u>Solution:
</u>
In this problem some of the basic trigonometric identities are used to prove the given expression.
Let’s first take the LHS:
Step one:
The sum of squares of Sine and Cosine is 1 which is:
On substituting the above identity in the given expression, we get,
Step two:
The reciprocal of cosine is secant which is:
On substituting the above identity in equation (1), we get,
Thus, RHS is obtained.
Using the identity , the given expression is verified.