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vlada-n [284]
2 years ago
10

two warehouse employees need to move microwave ovens and television that weigh 45 pounds and 85 pounds, respectively, using a fr

eight elevator. the freight elevator can hold a maximum of 2,400 pounds. the two employees and their loading equipment weigh 400 pounds. what is the maximum number of microwave ovens the two employees can take on the elevator if both employees, the loading equipment, and 20 televisions are in the elevator?
Mathematics
1 answer:
Zinaida [17]2 years ago
7 0

The maximum number of microwave ovens the two employees can take on the elevator is 7.

<h3>How to find the maximum number of microwave ovens the two employees can take on the elevator?</h3>

To solve the question, we have to find the simple equation showing the relationship between all the weights an the maximum weight the elevator can carry

Let

  • x = number of microwave ovens

Since the micro wave weighs 45 pounds, the total weight of microwave ovens is W = 45x.

Also, there are 20 televisions on the elevator. If each television weighs 85 pounds, the total weight of televisions is W' = 20 × 85 = 1700 pounds

Also, the weight of the equipment and the two employees is W" = 400 pounds.

Since the maximum weight on the elevator is 2400 pounds, we have that the required simple equation is

W + W' + W" = 2400

45x + 1700 + 400 = 2400

45x + 2100 = 2400

45x = 2400 - 2100

45x = 300

x = 300/45

x = 6.67

x ≅ 7

So, the maximum number of microwave ovens the two employees can take on the elevator is 7.

Learn more about simple equation here:

brainly.com/question/26184005

#SPJ1

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terms in a geometric sequence are 16, 20, 25, 31.25, find the value of the 17th term, to the nearest WHOLE number.
Bond [772]

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568

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I hope this was helpful

8 0
3 years ago
Part of the proceeds from a garage sale was $470 worth of $10 and $20 bills. If there were 14 more $10 bills than $20 bills, fin
Brums [2.3K]

There are 25 $10 bills and 11 $20 bills.

Step-by-step explanation:

Given,

Worth of proceeds from garage = $470

Let,

x be the number of $10 bills

y be the number of $20 bills.

According to given situation;

10x+20y=470       Eqn 1

x = y+14                Eqn 2

Putting value of x from Eqn 2 in Eqn 1

10(y+14)+20y=470\\10y+140+20y=470\\30y=470-140\\30y=330

Dividing both sides by 30

\frac{30y}{30}=\frac{330}{30}\\y=11

Putting y=11 in Eqn 2

x=11+14\\x=25

There are 25 $10 bills and 11 $20 bills.

Keywords: linear equation, substitution method

Learn more about linear equations at:

  • brainly.com/question/1279756
  • brainly.com/question/1284310

#LearnwithBrainly

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Simplify the expression -84 divided by 14
Nataliya [291]

easy peasy.

-84/14= -6

feel free to add me as a friend I am very good at math and am willing to help.

6 0
4 years ago
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