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tresset_1 [31]
2 years ago
5

PLEASE HELP I WILL GIVE BRAINLIEST

Mathematics
2 answers:
marysya [2.9K]2 years ago
6 0

Answer:

54

Step-by-step explanation:

Multiply:

<em>37x37=72</em>

<em>Subtract:</em>

<em>180-72=108</em>

<em>Divide:</em>

<em>108/2=54</em>

anygoal [31]2 years ago
6 0

Answer:

143 degrees

Step-by-step explanation:

37(2) + 2x = 360
74 + 2x = 360
2x = 286

x = 143

Hope this helps :)

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He will have more than enough because he only needs to cover 84.1425 square feet.
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3 years ago
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50 POINTS!! PLEASE ASAP. The director of a local ballet company needs to print the programs for the next performance. Janet’s Pr
Maru [420]

For this case we find the expression that represents the cost of each printing press.

x: Be the variable that represents the number of programs to print

So:

Cost 1: Janet’s Print Shop

C (x) = 0.25x + 35

Cost 2: The Printing Press

C (x) = 0.15x + 50

If we want to find the number of programs for which the costs are the same, then we equate both equations:

0.25x + 35 = 0.15x + 50\\0.25x-0.15x = 50-35\\0.1x = 15\\x = \frac {15} {0.1}\\x = 150

Thus, for 150 programs the cost is the same.

Answer:

For 150 programs the cost is the same.

5 0
3 years ago
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PLEASE HELP!!!
erastovalidia [21]

Step-by-step explanation:

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7 0
2 years ago
A credit card company charges 18.6% percent per year interest. Compute the effective annual rate if they compound, (a) annualy,
Darina [25.2K]

Answer:

a) Effective annual rate: 18.6%

b) Effective annual rate: 20.27%

c) Effective annual rate: 20.43%

d) Effective annual rate: 20.44%

Step-by-step explanation:

The effective annual interest rate, if it is not compounded continuously, is given by the formula

I=C(1+\frac{r}{n})^{nt}-C

where

<em>C = Amount of the credit granted </em>

<em>r = nominal interest per year </em>

<em>n = compounding frequency </em>

<em>t = the length of time the interest is applied. In this case, 1 year. </em>

In the special case the interest rate is compounded continuously, the interest is given by

I=Ce^{rt}-C

(a)  Annually

I=C(1+\frac{0.186}{1})-C=C(1.186)-C=C(1.186-1)=C(0.186)

The effective annual rate is 18.6%

(b) Monthly

<em>There are 12 months in a year </em>

I=C(1+\frac{0.186}{12})^{12}-C=C(1.2027)-C=C(0.2027)

The effective annual rate is 20.27%

(c) Daily

<em>There are 365 days in a year </em>

I=C(1+\frac{0.186}{365})^{365}-C=C(1.2043)-C=C(0.2043)

The effective annual rate is 20.43%

(d)  Continuously

I=Ce^{0.186}-C=C(1.2044)-C=C(0.2044)

The effective annual rate is 20.44%

3 0
2 years ago
Helppp aaaaaaaaaaaaaaAaaaa
vitfil [10]
The first one is C and the second one is B
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2 years ago
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