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ivanzaharov [21]
3 years ago
15

Emma created the poster shown below: A rectangle is shown. The length of the rectangle is labeled as length equal to 36 cm, and

the width is labeled as width equal to 24 cm. What would be the dimensions of the poster at fraction 1 over 4 times its current size? Length = 32 cm, width = 20 cm Length = 40 cm, width = 28 cm Length = 144 cm, width = 96 cm Length = 9 cm, width = 6 cm
Mathematics
2 answers:
Kruka [31]3 years ago
7 0
The answer is D. Length = 9, width = 6cm

Bingel [31]3 years ago
3 0

Answer:

Length = 9 cm, width = 6 cm

Step-by-step explanation:

If the length of the rectangle is labeled as length equal to 36 cm, and the width is labeled as width equal to 24 cm.

Length = 36cm

Width = 24cm

One fourth the current size of the rectangle will be;

New length= 1/4×36 = 9cm

New width = 1/4 × 24 = 6cm

The new dimension of the poster is therefore 9cm×6cm

Length = 9cm

Width = 6cm

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Answer:

Final answer is approx 6.644 years.

Step-by-step explanation:

Given that a company sold 5.75 million motorcycles and 3.5 million cars in the year 2010. The growth in the sale of motorcycles is 16% every year and that of cars is 25% every year.

So we can use growth formula:

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Now we need to find about when the sale of cars will be more than the sale of motorcycles. So we get:

3.5\left(1+0.25\right)^t>5.75\left(1+0.16\right)^t

3.5\left(1.25\right)^t>5.75\left(1.16\right)^t

3.5\left(1.25\right)^t>5.75\left(1.16\right)^t

\frac{\left(1.25\right)^t}{\left(1.16\right)^t}>\frac{5.75}{3.5}

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