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Mumz [18]
4 years ago
12

Choose numbers to fill in bar model

Mathematics
1 answer:
mash [69]4 years ago
7 0
1 7 3 2 and 3825 986
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2logbase4(x)-logbase4(5)=125
Goryan [66]
D:x>0\\\\ 2\log_4x-\log_45=125\\ \log_4x^2-\log_45=\log_44^{125}\\ \log_4\dfrac{x^2}{5}=\log_44^{125}\\ \dfrac{x^2}{5}=4^{125}\\ x^2=5\cdot4^{125}=5\cdot2^{250}=5\cdot(2^{125})^2\\ x=\sqrt{5\cdot2^{250}} \vee x=-\sqrt{5\cdot2^{250}}\\ x=\sqrt{5\cdot4^{125}} \vee x=-\sqrt{5\cdot4^{125}}\\ x=\sqrt{5\cdot(2^{125})^2} \vee x=-\sqrt{5\cdot(2^{125})^2}\\ x=\sqrt5 \cdot\sqrt{(2^{125})^2} \vee x=-\sqrt5 \cdot\sqrt{(2^{125})^2} \\ x=2^{125}\sqrt5 \vee x=-2^{125}\sqrt5

x=-2^{125}\sqrt5 \not \in D\Rightarrow \boxed{x=2^{125}\sqrt5}
7 0
3 years ago
PLEASE HELP ME I NEED THIS DONE ASAP !!!
Maurinko [17]

Answer:

20

Step-by-step explanation:

the number next to the variable is the coefficient.

20 is the coefficient, while w is the variable

7 0
3 years ago
Hey can you guys answer this pls
guajiro [1.7K]

Answer:

2/9 + 7/9 = 1

8 0
3 years ago
Needing help with some of my college summer HW
Arte-miy333 [17]

B. Half the speed of the car. and C. The number of different colors on the page.


Variables are symbols for unknown values, so you have to find the statements that contain an unknown value.


A. 27 ⇒ The point value is known, so there is no variable.

B. \frac{1}{2}X ⇒ Since the speed of the car is unknown, the variable X represents the speed of the car. This variable is multiplied by \frac{1}{2} or divided by 2 to get half the speed of the car.

C. X ⇒ The number of different colors is not known, so the variable X represents the number of different colors.

D. 80 ⇒ There is nothing unknown in the statement.


5 0
3 years ago
The table represents a linear function. Find the values of A and B.​
bazaltina [42]

Answer:

The answers are that a = -5 and b = 1

Step-by-step explanation:

In order to find A and B, we first need to find the equation of the line. We can do this by using two ordered pairs and the slope formula. For the purpose of this activity, I'l use (0, 5) and (-3, 11)

m(slope) = (y2 - y1)/(x2 - x1)

m = (11 - 5)/(-3 - 0)

m = 6/-3

m = -2

Now that we have this we can model this using point-slope form.

y - y1 = m(x - x1)

y - 5 = -2(x - 0)

y - 5 = -2x

y = -2x + 5

Now that we have the modeled equation we can use the ordered pair (a, 15) to solve for a.

y = -2x + 5

15 = -2(a) + 5

10 = -2a

-5 = a

And we can also solve for b using the ordered pair (2, b)

y = -2x + 5

b = -2(2) + 5

b = -4 + 5

b = 1

4 0
3 years ago
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