The triangle inequality requires the third side be in the range
.. 12 -4 ≤ third side ≤ 12 +4
.. 8 ≤ third side ≤ 16 . . . . . . . . . your answer is the number(s) in this range
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Some define the triangle inequality using < rather than ≤. Be careful here.
We're looking for the two values being subtracted here. One of these values is easy to find:
<span>g(1) = ∫f(t)dt = 0</span><span>
since taking the integral over an interval of length 0 is 0.
The other value we find by taking a Left Riemann Sum, which means that we divide the interval [1,15] into the intervals listed above and find the area of rectangles over those regions:
</span><span>Each integral breaks down like so:
(3-1)*f(1)=4
(6-3)*f(3)=9
(10-6)*f(6)=16
(15-10)*f(10)=10.
So, the sum of all these integrals is 39, which means g(15)=39.
Then, g(15)-g(1)=39-0=39.
</span>
I hope my answer has come to your help. God bless and have a nice day ahead!
Answer:
The answer to your question is a) (f°g)(x) = 4x² + 2
b) (f + g)(x) = 4x² + x + 2
c) (f - g)(-3) = -37
Step-by-step explanation:
Data
f(x) = x + 2
g(x) = 4x²
a) Calculate (f°g)(x)
Just sum the function
(f°g)(x) = (4x²) + 2
-Simplification
(f°g)(x) = 4x² + 2
b) (f + g)(x)
(f + g)(x) = x + 2 + 4x²
-Simplification
(f + g)(x) = 4x² + x + 2
c) (f - g)(-3)
-Calculate (f - g)(x)
(f - g)(x) = x + 2 - 4x²
-Simplify
(f - g)(x) = -4x² + x + 2
-Evaluate in (-3)
(f - g)(-3) = -(4)(-3)² + (-3) + 2
-Simplification
(f - g)(-3) = -4(9) - 3 + 2
-Result
(f - g)(-3) = -36 - 3 + 2
(f - g)(-3) = -37
Answer
The answer is B
Step-by-step explanation:
Answer:
To draw this graph, we start from the left in quadrant 3 drawing the curve to -4 on the x-axis to touch it but not cross. We continue back down and curve back around to cross the x-axis at -1. We continue up past -1 and curve back down to 5 on the x-axis. We touch here without crossing and draw the rest of our function heading back up. It should form a sideways s shape.
Step-by-step explanation:
A polynomials is an equation with many terms whose leading term is the highest exponent known as degree. The degree or exponent tells how many roots exist. These roots are the x-intercepts.
This polynomial has roots -4, -1, and 5. This means the graph must touch or cross through the x-axis at these x-values. What determines if it crosses the x-axis or the simple touch it and bounce back? The even or odd multiplicity - how many times the root occurs.
In this polynomial:
Root -4 has even multiplicity of 4 so it only touches and does not cross through.
Root -1 has odd multiplicity of 3 so crosses through.
Root 5 has even multiplicity of 6 so it only touches and does not cross through.
Lastly, what determines the facing of the graph (up or down) is the leading coefficient. If positive, the graph ends point up. If negative, the graph ends point down. All even degree graphs will have this shape.
To draw this graph, we start from the left in quadrant 3 drawing the curve to -4 on the x-axis to touch it but not cross. We continue back down and curve back around to cross the x-axis at -1. We continue up past -1 and curve back down to 5 on the x-axis. We touch here without crossing and draw the rest of our function heading back up. It should form a sideways s shape.