To answer A you have to find 0.5% of 151 because the heart is 0.5% of total body weight. 151 x 0.5% = 0.755 lbs
Answer:
pyramid, cone, sphere, cube
Answer:
Explanation:
The horizontal component of the velocity = 19.5 cos 36.5 = 15.67m /s
The vertical component = 19.5 sin36.5 = 11.6 m /s
height h = 15.5
we shall first find the time of fall of the ball into water
vertical displacement = height = 15.5 ( positive and g will be positive as it is downwards .
s = ut + 1/2 gt²
15.5 = - 19.5 sin36.5 t + 1/2 x 9.8 x t²
4.9 t² - 11.6 t - 15.5 = 0
t = 3.31 s
During this period ball will travel in horizontal velocity of 15.67 m /s uniformly
horizontal displacement before touching water
= 3.3 x 15.67
= 51.7 m .
Answer:
Explanation:
If we ASSUME that angular acceleration is constant and the desired output is angular distance.
The average angular velocity is
ω = (3 + 25) / 2 = 14 rad/s
θ = ωt = 14(10) = 140 radians
Answer:
The specific heat capacity of molybdenum is
0.2696 joule/gram
Explanation:
Step one
Given that
Mass of molybdenum Mm =237g
Temperature of molybdenum
T1=100°c
Mass of water MW =244g
Temperature of water T2= 10°c
Final temperature T3 =15.3°c
Step two :
We know that the specific heat capacity of water Cw 4.186 joule/gram
But Specific heat capacity of molybdenum Cm?
We know that the quantity of heat transfered can be expressed as
Q=Mm*Cm(T1-T3)+MW*Cw(T2-T3)
since the system attained thermal equilibrium then the expression
Is
=Mm*Cm(T1-T3)=MW*Cw(T3-T2)
Substituting our values into the equation we have
237*Cm(100-15.3)=244*4.186(15.310)
20073.9Cm=5413.3352
Cm=0.2696 joule/gram
Specific heat capacity of molybdenum is 0.2696 joule/gram