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lora16 [44]
3 years ago
9

If a train is travelling 200km/hour eastward for 1800 seconds how far does it travel?

Physics
1 answer:
Olenka [21]3 years ago
5 0

Answer:

Distance, d = 99990 meters

Explanation:

It is given that,

Speed of the train, v = 200 km/h = 55.55 m/s

Time taken, t = 1800 s

Let d is the distance covered by the train. We know that the speed of an object is given by total distance covered divided by total time taken. Mathematically, it is given by :

v=\dfrac{d}{t}

d=v\times t

d=55.55\times 1800

d = 99990 m

So, the distance covered by the train is 99990 meters. Hence, this is the required solution.

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Calculate the linear acceleration of a car, the 0.220-m radius tires of which have an angular acceleration of 13.0 rad/s2. Assum
Anuta_ua [19.1K]

Answer:

The linear acceleration of the car is 2.86m/s².

Explanation:

First of all, we have that the linear acceleration of the car and the tires is the same, because it moves ahead without disassembling itself. So, we only have to calculate the linear acceleration of the tires.

Next, it is known that the linear and angular acceleration are related by the formula:

a=\alpha R

Finally, we plug in the given values in order to calculate the acceleration:

a=(13.0rad/s^{2})(0.220m)=2.86m/s^{2}

It means that the linear acceleration of the car is 2.86m/s².

6 0
4 years ago
What factor determines an object's momentum?
vlada-n [284]

Momentum = mass x velocity

So both mass and velocity affect an object's momentum.

3 0
3 years ago
A rifle fires a 2.10 x 10^-2 kg pellet straight upward, because the pellet rests on a compressed spring when the trigger is is p
yKpoI14uk [10]

m = mass of pellet = 2.10 x 10⁻² kg

x = compression of spring at the time launch = 9.10 x 10⁻² m

h = height gained by the pellet above the initial position = 6.10 m

k = spring constant

using conservation of energy

spring potential energy = gravitational potential energy of pellet

(0.5) k x² = m g h

inserting the values

(0.5) k (9.10 x 10⁻²)² = (2.10 x 10⁻²) (9.8) (6.10)

k = 303.2 N/m

4 0
3 years ago
HELP ME PLZ
Nadusha1986 [10]

Answer: 1200 000 J = 1.2 MJ

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3 0
3 years ago
The 25-mph zone is 150 yards long. How much time did the student save (in seconds) by speeding past the school
VikaD [51]

Answer:

Time = 12.27seconds

Explanation:

Given

Speed = 25miles/hour

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7 0
3 years ago
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