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Lerok [7]
3 years ago
14

How to cure bor-edom????

Physics
2 answers:
Allisa [31]3 years ago
4 0

Answer:

keep ur self busy

Explanation:

read a book

catch up on homework

get ahead of the class

watch tv

go outside

Colt1911 [192]3 years ago
3 0

Answer:

I honestly would get out of the house and just wonder off to places that soothe me the most or I would get really lit and just jam out to some music

Explanation:

I hope this can help ya!!!!

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What does your ecological foot print tell you?
shepuryov [24]

Answer:

How big your foot is. (Big Brain)

Explanation:

3 0
4 years ago
If x2 = 60, what is the value of x? plus or minus square root 30 plus or minus square root 60 ±30 ±120
Zielflug [23.3K]
X2 = 60
/ 2 / 2
x = 30
Plus or minus square root 60
4 0
3 years ago
A mass m = 0.6 kg is released from rest at the top edge of a hemispherical bowl with radius = 1.1 meters. The mass then slides w
Aneli [31]

Answer:

The  angle is  \theta   = 36.24 ^o

Explanation:

From the question we are told that

    The  mass is  m  =  0.6 \ kg

     The radius is  r =  1.1 \ m

     The speed is  v =  3.57 \ m /s

According to  the law of energy conservation

  The  potential energy of the mass at the top is equal to the kinetic energy at the bottom i.e

      m * g  *  h  =  \frac{1}{2}  *  m * v^2

 =>    h  =  \frac{1}{2 g } *  v^2

Here h is the vertical distance traveled by the mass  which is also mathematically represented as

      h  =  r * sin (\theta )

So

     \theta   = sin ^{-1} [ \frac{1}{2* g* r } *  v^2]

substituting values

     \theta   = sin ^{-1} [ \frac{1}{2* 9.8* 1.1 } *  (3.57)^2]

     \theta   = 36.24 ^o

3 0
4 years ago
A pump lifts water from a lake to a large tank 20 m above the lake. How much work against gravity does the pump do as it transfe
Aleonysh [2.5K]

Answer:

980 kJ

Explanation:

Work = change in energy

W = mgh

W = (1000 kg/m³ × 5.0 m³) (9.8 m/s²) (20 m)

W = 980,000 J

W = 980 kJ

The pump does 980 kJ of work.

3 0
3 years ago
Read 2 more answers
A car's bumper is designed to withstand a 6.84 km/h (1.9-m/s) collision with an immovable object without damage to the body of t
den301095 [7]

Answer:

F = 5.256 x 10^{3} N

Explanation:

From the work energy theorem we know that:

The net work done on a particle equals the change in the particles kinetic energy:

W = F.d, ΔK =\frac{1}{2} mv^{2}_{f}   - \frac{1}{2} mv^{2}_{i}  , F.d = \frac{1}{2}mv^{2}_{f} -\frac{1}{2} mv^{2}_{i}

where:

W = work done by the force

F = Force

d = Distance travelled

m = Mass of the car

vf, vi = final and initial velocity of the car

kf, ki = final and initial kinetic energy of the car

Given the parameters;

m = 830kg

vi = 1.9 m/s

vf = 0 km/h

d = 0.285 m

Inserting the information we have:

F.d = \frac{1}{2} mv^{2}_{f}   - \frac{1}{2} mv^{2}_{i}

F = \frac{\frac{1}{2} mv^{2}_{f}   - \frac{1}{2} mv^{2}_{i} }{d}

F = \frac{ 0   - \frac{1}{2}  X830 X 1.9^{2} }{0.285}

F = 5.256 x 10^{3} N

3 0
3 years ago
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