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topjm [15]
1 year ago
11

If the equilibrium concentrations are 1. 01 m a, 1. 51 m b, and 2. 05 m c. Calculate the value of the equilibrium constant of th

e reverse reaction.
Chemistry
1 answer:
pogonyaev1 year ago
3 0

0.182 is the value of the equilibrium constant of the reverse reaction.

Given reaction i.e. Forward reaction

4A + B = 3C

If we reverse this reaction, the equation becomes

3C = 4A + B

Now, the equilibrium-constant statement for the reverse reaction is the opposite of the equilibrium-constant expression for the forward reaction.

Equilibrium constant =  [A]⁴ × [B] / [C]³

The concentrations can be used to compute K(reverse) once the formula for the equilibrium constant for the reverse reaction has been established.

Conc. of A = 1.01 M

Conc. of B = 1.51M

Conc. of C = 2.05 M

Kc for reverse reaction = [1.01]⁴ × [1.51]/ [2.05]³

                                       = 0.182

Hence, 0.182 is the value of the equilibrium constant of the reverse reaction.

Learn more about equilibrium constant here brainly.com/question/12858312

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Density gives mass of object per volume......   Here, density is given 8.90 g/cm3   therefore, per cubic centimeter contains 8.90 g Ni.   mole of Ni = mass / atomic mass   = 8.90 / 58.6934   = 0.1516 mole     number of atoms: mole * 6.022 * 10^23   = 0.1516 * 6.022 * 10^23   = 0.9129 * 10^23   = 0.9 * 10^23 (approx.)
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What is Lewis symbol for K+
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Lewis symbol for K+ is given by a dot and K.

<h3>Meaning of Lewis symbol</h3>

Lewis symbols can be defined as a symbol the is used in describing the valence electron configurations of an atom ions.

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In conclusion, Lewis symbol for K+ is given by a dot and K.

Learn more about Lewis symbol: brainly.com/question/6605265

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Lewis was a person of law

Explanation:

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