Question

If the equilibrium concentrations are 1. 01 m a, 1. 51 m b, and 2. 05 m c. Calculate the value of the equilibrium constant of the reverse reaction.

Answer 1

0.182 is the value of the equilibrium constant of the reverse reaction.

Given reaction i.e. Forward reaction

4A + B = 3C

If we reverse this reaction, the equation becomes

3C = 4A + B

Now, the equilibrium-constant statement for the reverse reaction is the opposite of the equilibrium-constant expression for the forward reaction.

Equilibrium constant =  [A]⁴ × [B] / [C]³

The concentrations can be used to compute K(reverse) once the formula for the equilibrium constant for the reverse reaction has been established.

Conc. of A = 1.01 M

Conc. of B = 1.51M

Conc. of C = 2.05 M

Kc for reverse reaction = [1.01]⁴ × [1.51]/ [2.05]³

                                       = 0.182

Hence, 0.182 is the value of the equilibrium constant of the reverse reaction.

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