According to the statement
2.12 x 10^4 lbs pounds of CaCO₃ are needed to neutralize this acid
<h3>What is neutralization?</h3>
A chemical reaction in which an acid and a base react quantitatively with each other is known as neutralization or neutralization. In a water reaction, neutralization ensures that there is no excess of hydrogen or hydroxide ions in the solution.
<h3>According to the given information:</h3>
The equation of the neutralization reaction between H2SO4 and CaCO3.
CaCO3 + H2SO4 → CaSO4 + H2CO3
H2CO3 dissociate to water and carbon dioxide.
CaCO3 + H2SO4 → CaSO4 + H2O + CO2
Now solving for the mass of CaCO3 needed to neutralize the acid.
mass of CaCO3 = 9460 Kg H2SO4 × 
= 21284.56606
mass of CaCO3 = 2.12 x 10^4 lbs
2.12 x 10^4 lbs pounds of CaCO₃ are needed to neutralize this acid.
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The number of Ml of C₅H₈ that can be made from 366 ml C₅H₁₂ is 314.7 ml of C₅H₈
<u><em>calculation</em></u>
step 1: write the equation for formation of C₅H₈
C₅H₁₂ → C₅H₈ + 2 H₂
Step 2: find the mass of C₅H₁₂
mass = density × volume
= 0.620 g/ml × 366 ml =226.92 g
Step 3: find moles Of C₅H₁₂
moles = mass÷ molar mass
from periodic table the molar mass of C₅H₁₂ = (12 x5) +( 1 x12) = 72 g/mol
moles = 226.92 g÷ 72 g/mol =3.152 moles
Step 4: use the mole ratio to determine the moles of C₅H₈
C₅H₁₂:C₅H₈ is 1:1 from equation above
Therefore the moles of C₅H₈ is also = 3.152 moles
Step 5: find the mass of C₅H₈
mass = moles x molar mass
from periodic table the molar mass of C₅H₈ = (12 x5) +( 1 x8) = 68 g/mol
= 3.152 moles x 68 g/mol = 214.34 g
Step 6: find Ml of C₅H₈
=mass / density
= 214.34 g/0.681 g/ml = 314.7 ml
I calculated is and the answer is 1272.0600000000002.
I really don't know how to explain it
