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3 years ago

Choose the formula for hydroxide. OH HPO4 Ca(OH)2 d Ba(OH)2

Chemistry

2 answers:

yKpoI14uk [10]3 years ago

5 0

OH that’s the answer OH

dimulka [17.4K]3 years ago

4 0

Answer:

Explanation:

Hydroxide is a diatomic anion with chemical formula OH⁻.

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Q- Which two positions show the location of the moon in its gibbous phases as seen from Earth?

Phoenix [80]

Answer: 6 & 8

Explanation:

I got it correct on my test hope this helped

4 0

3 years ago

Are two atoms of the same element identical??

Neko [114]

No. Although two such atoms are essentially chemically identical (they will chemically react in the same way), they are not completely identical.

3 0

3 years ago

Thorium-234 has a half-life of 24.1 days. How many grams of a 150 g sample would you have after 120.5 days?

chubhunter [2.5K]

Answer:

8.625 grams of a 150 g sample of Thorium-234 would be left after 120.5 days

Explanation:

The nuclear half life represents the time taken for the initial amount of sample to reduce into half of its mass.

We have given that the half life of thorium-234 is 24.1 days. Then it takes 24.1 days for a Thorium-234 sample to reduced to half of its initial amount.

Initial amount of Thorium-234 available as per the question is 150 grams

So now we start with 150 grams of Thorium-234

$150 \times \frac{1}{2}=24.1$

$75 \times \frac{1}{2} =48.2$

$34.5 \times \frac{1}{2} =72.3$

$17.25 \times \frac{1}{2} =96.4$

$8.625\times \frac{1}{2} =120.5$

So after 120.5 days the amount of sample that remains is 8.625g

In simpler way , we can use the below formula to find the sample left

$A=A_{0} \cdot \frac{1}{2^{n}}$

Where

$A_0$ is the initial sample amount

n = the number of half-lives that pass in a given period of time.

7 0

3 years ago

I will mark brainliest

blondinia [14]

Answer:

1. sovent

2. solute

3. solutability

Explanation:

3 0

2 years ago

In what way(s) is(are) the structure of water similar to that of CHCl3? In what way is the structure of water different from tha

Lapatulllka [165]

Answer:

See explanation below

Explanation:

In both cases the central atoms, C in CHCl₃ and O in H₂O, are sp³ hybridized .

Since they are sp³ hybridized we predict an angle between the H-C-Cl and H-O-H of 109.5 º ( tetrahedral ), but two of the sp³ orbitals in water are occupied by lone pairs.

These lone pairs do excercise more repulsion ( need more room ) than the bonds oxygen is making with hydrogen.

As a consequence of this repulsion the angles H-O-H are less than the predicted 109.5º in tetrahedra. ( Actually is 104.5 º)

5 0

3 years ago