Answer:
A) pH of the buffer is 3.44
B) pH of the buffer solution is 3.37
Explanation:
Relation between K_{a} and pK_{a} is as follows.

.

The relation between pH and pK_{a} is as follows.
![pH = pK_{a} + log\frac{[conjugate base]}{[acid]}](https://tex.z-dn.net/?f=pH%20%3D%20pK_%7Ba%7D%20%2B%20log%5Cfrac%7B%5Bconjugate%20base%5D%7D%7B%5Bacid%5D%7D)

pH of the buffer is 3.44.
b)
mol of HCl added = 11.6M *0.001 L = 0.0116 mol
In the given reaction,
will react with
to form
No. of moles of

And, no. of moles of 
= 0.12 mol
after the reaction :
No. of moles of
= moles present initially - moles added
= (0.15 - 0.0116) mol
= 0.1384 mol
Moles of
= moles present initially + moles added
= (0.12 + 0.0116)
= 0.1316 mol
As,

Since, volume is both in numerator and denominator, we can use mol instead of concentration.
![pH = pK_{a} + log \frac{[conjugate base]}{[acid]}](https://tex.z-dn.net/?f=pH%20%3D%20pK_%7Ba%7D%20%2B%20log%20%5Cfrac%7B%5Bconjugate%20base%5D%7D%7B%5Bacid%5D%7D)
= 3.347+ log {0.1384/0.1316}
= 3.369
≅ 3.37
pH after the addition of 1.00 mL of 11.6 M HCl to 1.00 L of the buffer solution is 3.37
Answer:
La constante de equilibrio Ka del ácido láctico es 1.38x10⁻⁴.
Explanation:
El ácido láctico es un ácido débil cuya reacción de disociación es la siguiente:
CH₃CHOHCOOH + H₂O ⇄ CH₃CHOHCOO⁻ + H₃O⁺ (1)
0.025M - x x x
La constante de acidez del ácido es:
![Ka = \frac{[CH_{3}CHOHCOOH^{-}][H_{3}O^{+}]}{[CH_{3}CHOHCOOH]}](https://tex.z-dn.net/?f=%20Ka%20%3D%20%5Cfrac%7B%5BCH_%7B3%7DCHOHCOOH%5E%7B-%7D%5D%5BH_%7B3%7DO%5E%7B%2B%7D%5D%7D%7B%5BCH_%7B3%7DCHOHCOOH%5D%7D%20)
Sabemos que la concentración del ácido inicial es:
[CH₃CHOHCOOH] = 0.025 M
Y que a partir del pH podemos hallar [H₃O⁺]:
![pH = -log[H_{3}O^{+}]](https://tex.z-dn.net/?f=%20pH%20%3D%20-log%5BH_%7B3%7DO%5E%7B%2B%7D%5D%20)
![[H_{3}O^{+}] = 10^{-pH} = 10^{-2.75} = 1.78 \cdo 10^{-3} M](https://tex.z-dn.net/?f=%20%5BH_%7B3%7DO%5E%7B%2B%7D%5D%20%3D%2010%5E%7B-pH%7D%20%3D%2010%5E%7B-2.75%7D%20%3D%201.78%20%5Ccdo%2010%5E%7B-3%7D%20M%20)
Debido a que el ácido se disocia en agua para producir los iones CH₃CHOHCOO⁻ y H₃O⁺ de igual manera (según la reacción (1)), tenemos:
[CH₃CHOHCOO⁻] = [H₃O⁺] = 1.78x10⁻³ M
Y por esa misma disociación, la concentración del ácido en el equilibrio es:
![[CH_{3}CHOHCOOH^{-}] = 0.025 M - 1.78 \cdo 10^{-3} M = 0.023 M](https://tex.z-dn.net/?f=%20%5BCH_%7B3%7DCHOHCOOH%5E%7B-%7D%5D%20%3D%200.025%20M%20-%201.78%20%5Ccdo%2010%5E%7B-3%7D%20M%20%3D%200.023%20M%20)
Entonces, la constante de equilibrio Ka del ácido láctico es:
Espero que te sea de utilidad!
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Each gas dissolved in the blood diffuses between the blood and its surroundings based on differences in the partial pressure and diffusion occurs until equilibrium is reached.
<h3>What is the gas exchange in bloodstream?</h3>
The gas exchange refers to the process by which oxygen is absorbed by red blood cells and carbon dioxide is removed through the respiratory system.
The process of gas exchange is carried out due to the differential diffusion rates of gases in the bloodstream (O2 and CO2), which facilitates the transference of these gases.
In conclusion, each gas dissolved in the blood diffuses between the blood and its surroundings based on differences in the partial pressure and diffusion occurs until equilibrium is reached.
Learn more about gas exchange in bloodstream here:
brainly.com/question/17920029
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