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Bond [772]
3 years ago
6

Choose the formula for hydroxide. OH HPO4 Ca(OH)2 d Ba(OH)2

Chemistry
2 answers:
yKpoI14uk [10]3 years ago
5 0
OH that’s the answer OH
dimulka [17.4K]3 years ago
4 0

Answer:

OH

Explanation:

Hydroxide is a diatomic anion with chemical formula OH⁻.

You might be interested in
A buffer consists of 0.120 m hno2 and 0.150 m nano2 at 25°c.
wolverine [178]

Answer:

A) pH of the buffer is 3.44

B) pH of the buffer solution is 3.37

Explanation:

Relation between K_{a} and pK_{a} is as follows.

pK_{a} = -log (K_{a})

. pK_{a} = -log (K_{a})                                    = -log(4.5 \times 10^{-4})                                     = 3.347

The relation between pH and  pK_{a} is as follows.

pH = pK_{a} + log\frac{[conjugate base]}{[acid]}

= 3.347+ log \frac{0.15}{0.12}                    = 3.44

pH of the buffer is 3.44.

b)

mol of HCl added = 11.6M *0.001 L = 0.0116 mol

In the given reaction, NO^{-}_{2} will react with H^{+} to formHNO_{2}

No. of moles of

NO^{-}_{2} = 0.15 M \times 1.0 L                                           = 0.15 mol

And, no. of moles of HNO_{2} = 0.12 M \times 1.0 L

                                              = 0.12 mol

after the reaction :  

No. of moles of NO^{-}_{2} = moles present initially - moles added

                                         = (0.15 - 0.0116) mol

                                         = 0.1384 mol

Moles of HNO_{2} = moles present initially + moles added

                = (0.12 + 0.0116)

                = 0.1316 mol

As,

K_{a} = 4.5 \times 10^{-4}           pK_{a} = -log (K_{a})                         = -log(4.5 \times 10^{-4})                         = 3.347

Since, volume is both in numerator and denominator, we can use mol instead of concentration.

pH = pK_{a} + log \frac{[conjugate base]}{[acid]}

= 3.347+ log {0.1384/0.1316}

           = 3.369

           ≅ 3.37

pH after the addition of 1.00 mL of 11.6 M HCl to 1.00 L of the buffer solution is 3.37

4 0
3 years ago
Si tenemos una solución de ácido láctico 0.025M con un pH = 2.75. ¿Cuál es la constante de equilibrio Ka?
rodikova [14]

Answer:

La constante de equilibrio Ka del ácido láctico es 1.38x10⁻⁴.

Explanation:

El ácido láctico es un ácido débil cuya reacción de disociación es la siguiente:

CH₃CHOHCOOH + H₂O ⇄ CH₃CHOHCOO⁻ + H₃O⁺   (1)

0.025M - x                                        x                     x                    

La constante de acidez del ácido es:        

Ka = \frac{[CH_{3}CHOHCOOH^{-}][H_{3}O^{+}]}{[CH_{3}CHOHCOOH]}

Sabemos que la concentración del ácido inicial es:

[CH₃CHOHCOOH] = 0.025 M    

Y que a partir del pH podemos hallar [H₃O⁺]:

pH = -log[H_{3}O^{+}]

[H_{3}O^{+}] = 10^{-pH} = 10^{-2.75} = 1.78 \cdo 10^{-3} M

Debido a que el ácido se disocia en agua para producir los iones CH₃CHOHCOO⁻ y H₃O⁺ de igual manera (según la reacción (1)), tenemos:

[CH₃CHOHCOO⁻] = [H₃O⁺] = 1.78x10⁻³ M

Y por esa misma disociación, la concentración del ácido en el equilibrio es:

[CH_{3}CHOHCOOH^{-}] = 0.025 M - 1.78 \cdo 10^{-3} M = 0.023 M

Entonces, la constante de equilibrio Ka del ácido láctico es:

Ka = \frac{[CH_{3}CHOHCOOH^{-}][H_{3}O^{+}]}{[CH_{3}CHOHCOOH]} = \frac{(1.78 \cdo 10^{-3})^{2}}{0.023} = 1.38 \cdot 10^{-4}          

 

Espero que te sea de utilidad!  

3 0
3 years ago
Plastics are synthetic, organic polymers. how are plastics similar and different to polysaccharides
yawa3891 [41]
Plastics and polysaccharides are somewhat similar because they are both polymers. Polymers are a long chain of repeating units called monomers. Their difference, however, is the identity of their monomers. Plastics have hydrocarbons as monomers. Plastics with the monomer ethene is called polyethylene. For polysaccharides, their monomers are simple sugars.
6 0
4 years ago
Each gas dissolved in the blood diffuses between the blood and its surroundings based on differences in the partial pressure bet
yawa3891 [41]

Each gas dissolved in the blood diffuses between the blood and its surroundings based on differences in the partial pressure and diffusion occurs until equilibrium is reached.

<h3>What is the gas exchange in bloodstream?</h3>

The gas exchange refers to the process by which oxygen is absorbed by red blood cells and carbon dioxide is removed through the respiratory system.

The process of gas exchange is carried out due to the differential diffusion rates of gases in the bloodstream (O2 and CO2), which facilitates the transference of these gases.

In conclusion, each gas dissolved in the blood diffuses between the blood and its surroundings based on differences in the partial pressure and diffusion occurs until equilibrium is reached.

Learn more about gas exchange in bloodstream here:

brainly.com/question/17920029

#SPJ1

8 0
2 years ago
Really need help with the rest of them, please it's due in 20 minutes
ArbitrLikvidat [17]

Answer:

chlorine is for pool

Explanation:

hope is help

8 0
3 years ago
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