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joja [24]
2 years ago
10

Michael can pack 10 parcels in 3 minutes. Kate can pack 7 parcels in 2 minutes. If they work together, how many parcels can they

pack in 5 minutes?​
Mathematics
1 answer:
Mariulka [41]2 years ago
8 0

Answer:

<u>37.5 parcels </u>in 5 minutes.  Round down to 37, if required for the purpose of the calculation.

Step-by-step explanation:

Let M and K be the rates Michael and Kate can pack parcels, in parcels/minute, or p/m.

M = (10/3)p/m

K = (7/2)p/m

When they work together for 5 minutes, we can calculate the numbers of parcels each pack.

Michael:  ((10/3)p/m)*(5m) = 20 p

Kate:        ((7/2)p/m)*(5m) =  17.5 p

                             Total  =    37.5 parcels

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nadezda [96]
205.1000>0.205
There is no number before the decimal for 0.205, therefore it is less than. If there was a number before the decimal, you would have to "calculate" whether or not it is greater than 205.1000 starting from .1000. 
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3 years ago
75,15,3 find the 6th term
Karolina [17]

Answer:

0.024

Step-by-step explanation:

75, 15, 3, ...

Now, let's take a look at thus pattern.

You'll notice how the numbers decrease.

Divide 75 by 5.

We get 15

Divide 15 by 5.

We get 3.

Then we have the pattern now.

3 ÷ 5 = 0.6 (4th term)

0.6 ÷ 5 = 0.12 (5th term)

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I hope it helps.

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3 years ago
Can you do it step by step for me
liraira [26]

Answer:

= 10

Step-by-step explanation:

r + (s+1)^{2} ÷ 3

if, r = 7 and s = 2

SO..

7 + (2+1)^{2} ÷ 3

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Add 2 and 1 to get 3.

7 + \frac{3^{2} }{3}

Calculate 3 to the power of 2 and get 9.

7 + \frac{9}{3}

Divide 9 by 3 to get 3.

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7 0
3 years ago
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Quadrilateral ABCD is inscribed in the circle. If m∠A = 95°, what also must be true?
Shalnov [3]
When a quadrilateral is inscribed in a circle, the sum of opposite angles is 180 degrees.  

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Therefore the answer is B). I hope this helped. 
3 0
3 years ago
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Unit 1 geometry basics quiz 1-3 angle measures and relationships
ASHA 777 [7]

Answer/Step-by-step explanation:

1. Side CD and side DG meet at endpoint D to form <4. Therefore, the sides of <4 are:

Side CD and side DG.

2. Vertex of <2 is the endpoint at which two sides meet to form <2.

Vertex of <2 is D.

3. Another name for <3 is <EDG

4. <5 is less than 90°. Therefore, <5 can be classified as an acute angle.

5. <CDE is less than 180° but greater than 90°. Therefore, <CDE is classified as an obtuse angle.

6. m<5 = 42°

m<1 = 117°

m<CDF = ?

m<5 + m<1 = m<CDF (angle addition postulate)

42° + 117° = m<CDF (Substitution)

159° = m<CDF

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7. m<3 = 73°

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m<FDE = 17°

3 0
3 years ago
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