THIS IS THE COMPLETE QUESTION BELOW
The demand equation for a product is p=90000/400+3x where p is the price (in dollars) and x is the number of units (in thousands). Find the average price p on the interval 40 ≤ x ≤ 50.
Answer
$168.27
Step by step Explanation
Given p=90000/400+3x
With the limits of 40 to 50
Then we need the integral in the form below to find the average price
1/(g-d)∫ⁿₐf(x)dx
Where n= 40 and a= 50, then if we substitute p and the limits then we integrate
1/(50-40)∫⁵⁰₄₀(90000/400+3x)
1/10∫⁵⁰₄₀(90000/400+3x)
If we perform some factorization we have
90000/(10)(3)∫3dx/(400+3x)
3000[ln400+3x]₄₀⁵⁰
Then let substitute the upper and lower limits we have
3000[ln400+3(50)]-ln[400+3(40]
30000[ln550-ln520]
3000[6.3099×6.254]
3000[0.056]
=168.27
the average price p on the interval 40 ≤ x ≤ 50 is
=$168.27
4y - 8 - 2y + 5 = 0
2y - 3 = 0
2y = 3
y = 3/2
Answer:
search it
Step-by-step explanation:
"5 times a sum of 12 and a number is 80" translates to the next equasion:
5 x (12+a) = 80
Now we just have to solve it to find the value of a.
The unknown number is 4.
D is the right answer.
15 + 0.75x = 57
-15 -15
0.75x = 42
0.75x/0.75 = 42/0.75
x = 56 people
The student interviewed 56 people on the day he earned $57
