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patriot [66]
3 years ago
7

Find the distance, c, between (1, 2) and (4, –1) on the coordinate plane. Round to the nearest tenth if necessary.

Mathematics
1 answer:
MakcuM [25]3 years ago
3 0

Answer: 3\sqrt{2} = 4.24 = 4.2

Step-by-step explanation:

d = \sqrt{(x_2-x_1)^{2} +(y_2-y_1)^{2}

= fill in the distance formula

=3\sqrt{2}

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Alex17521 [72]
3.8 is the answer you already figured it out
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3 years ago
What is 6.8 to a fully simplified mixed number
Alisiya [41]
6.8

= 6 + 0.8

= 6 + 8/10 (simplifying...)

= 6 + (8 : 2)/(10 : 2)

= 6 + 4/5

= 6 4/5 <----- this is the answer.

I hope this helps. =)
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The sides of a triangle are 3x+2 6x-1 and 7-x express the perimeter in terms of x
Strike441 [17]

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3 0
3 years ago
each of exercises 15–30 gives a function ƒ(x) and numbers l, c, and e 7 0. in each case, find an open interval about c on which
3241004551 [841]

The given inequality holds for the open interval (2.97,3.03)

It is given that

f(x)=6x+7

cL=25

c=3

ε=0.18

We have,

|f(x)−L| = |6x+7−25|

          = |6x−18|

          = |6(x−3)|

          = 6|x−3|

Now,

6|x−3| <0.18  then |x−3|<0.03 ----->−0.03<x-3<0.03---->2.97<x<3.03

the given inequality holds for the open interval (2.97,3.03)

For more information on inequality click on the link below:

brainly.com/question/11613554

#SPJ4

Although part of your question is missing, you might be referring to this full question: For the given function f(x) and values of L,c, and ϵ0, find the largest open interval about c on which the inequality |f(x)−L|<ϵ holds. Then determine the largest value for δ>0 such that 0<|x−c|<δ→|f(x)−|<ϵ.

f(x)=6x+7,L=25,c=3,ϵ=0.18

 

.

6 0
2 years ago
F(x)=2x<br> f(3)<br> Use the following function rule to find
vovangra [49]

Step-by-step explanation:

Given

f(x) = 2x

f(3) = 2 * 3 = 6

Hope it will help):)

4 0
3 years ago
Read 2 more answers
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