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Wewaii [24]
1 year ago
13

4x+15=6x-5 solve for x

Mathematics
2 answers:
hram777 [196]1 year ago
6 0

Answer:

x = 10

Step-by-step explanation:

Breaking down the equation

4x+15=6x-5\\4x+15-15=6x-5-15\\4x=6x-20\\4x-6x=6x-20-6x\\-2x=-20\\\frac{-2x}{-2}=\frac{-20}{-2}

Simplification

\frac{-2x}{-2}\\=\frac{2x}{2} (\frac{-x}{-y} = \frac{x}{y})\\\frac{2}{2} = 1 = x\\\\\frac{-20}{-2}\\=\frac{20}{2}\\\frac{20}{2}\\=10

coldgirl [10]1 year ago
3 0

Answer:

x=-10

Step-by-step explanation:

Hi!

  • Subtract 6x from both sides.

\leadsto\boldsymbol{4x+15=6x-5}

\leadsto\boldsymbol{-2x+15=-5}

  • Subtract 15 from both sides.

\leadsto\boldsymbol{-2x=-20}

\leadsto\boldsymbol{x=-10}

Have a nice day! :)

<em>- Creative Daydreamer</em>

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olga_2 [115]

Answer:

see explanation

Step-by-step explanation:

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81 cm² ÷ 3 = 27 cm² ← value of 1 part of the ratio

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The side of the original square = \sqrt{81} = 9 cm

The width of both rectangles is 9 cm ( width remains unchanged after cut )

Thus

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length = 6 cm

Rectangle B

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Rectangle A → length = 6 cm, width = 9 cm

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3 years ago
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Given the graph below, which of the following points would be included in the graph of the inverse of the function?
Svetlanka [38]

Answer : (1,-1)

a line through the points (-1, 1), (0, 2), (1, 3)

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How much interest would be paid on $75 at 5% interest rate for 2 years??
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Answer:

Step-by-step explanation:

Step one: because fractions are out of 100% you do

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antoniya [11.8K]
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3 years ago
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Anastaziya [24]

Answer:

5x^2+7x+30+\frac{102}{x-3}

Step-by-step explanation:

\mathrm{Divide\:the\:leading\:coefficients\:of\:the\:numerator\:}5x^3-8x^2+9x+12\\\mathrm{and\:the\:divisor\:}x-3\mathrm{\::\:}\frac{5x^3}{x}=5x^2\\\mathrm{Quotient}=5x^2\\\mathrm{Multiply\:}x-3\mathrm{\:by\:}5x^2:\:5x^3-15x^2\\\mathrm{Subtract\:}5x^3-15x^2\mathrm{\:from\:}5x^3-8x^2+9x+12\mathrm{\:to\:get\:new\:remainder}\\\mathrm{Remainder}=7x^2+9x+12\\\mathrm{Therefore}\\=5x^2+\frac{7x^2+9x+12}{x-3}

\mathrm{Divide\:the\:leading\:coefficients\:of\:the\:numerator\:}7x^2+9x+12\\\mathrm{and\:the\:divisor\:}x-3\mathrm{\::\:}\frac{7x^2}{x}=7x\\\mathrm{Quotient}=7x\\\mathrm{Multiply\:}x-3\mathrm{\:by\:}7x:\:7x^2-21x\\\mathrm{Subtract\:}7x^2-21x\mathrm{\:from\:}7x^2+9x+12\mathrm{\:to\:get\:new\:remainder}\\\mathrm{Remainder}=30x+12\\\mathrm{Therefore}\\=5x^2+7x+\frac{30x+12}{x-3}\\

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