A light bulb consumes 960 watt-hours per day. How many watt-hours does it consume in 3 days and 18 hours?

Mathematics

2 answers:

oksano4ka [1.4K]3 years ago

7 0

960 x 3 = 2880

18/24 = 0.75

960x 0.75 = 720

2880 + 720 = 3600

Pie3 years ago

4 0

Okay. Let's explain this. 960 per day. So let's start simple: 3 days and 960 per day is basically 2880 total watt-hours. Then we must do the 18 hours. How? We must multiply it the same way we did with the whole days. So we recognize that 18 hours is 18/24 hours in a day which is simplified: 18/24, 9/12, 3/4. So basically 18 hours is 3/4 of a day. So then we must multiply it by 3/4 of 960. So 960 x 3 = 2880, 2880 / 4 = 720. So then we must add them all up: 2880 + 720 = 3600 watt-hours in 3 days and 18 hours.

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What is the area of the triangle?

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Answer:

7 square units

Step-by-step explanation:

There are several ways the area of triangle EBD can be found.

find the lengths EB, BD, DE and use Heron's formula (messy due to roots of roots being involved).
define point G at the lower left corner and subtract the areas of ∆DEG and BCD from trapezoid BCGE.
figure the area from the coordinates of the vertices.
use Pick's theorem and count the dots.

We choose the latter.

Pick's theorem says the area of a polygon can be found as ...

A = i + b/2 -1

where i is the number of grid intersection points interior to the polygon, b is the number of grid points intersected by the border.

The attached figure shows the lines EB, BD, and DE intersect one point in addition to the vertices. So, b=4. A count of the red dots reveals 6 interior points (i=6). So, the area is ...

A = 6 + (4/2) -1 = 7

The area of ∆EBD is 7 square units.