1.
the x value of the vertex in form
ax^2+bx+c=y
is
-b/2a
so
-2x^2+8x-18
x value of vertex is
-8/(2*-2)=-8/-4=2
plug it in to get y value
-2(2)^2+8(2)-18
-2(4)+16-18
-8-2
-10
vertex is at (2,-10)
or you could complete the square to get into y=a(x-h)^2+k, where the vertex is (h,k)
so as follows
y=(-2x^2+8x)-18
y=-2(x^2-4x)-18
y=-2(x^2-4x+4-4)-18
y=-2((x-2)^2-4)-18
y=-2(x-2)^2+8-18
y=-2(x-2)^2-10
vertex is (2,-10)
5.
vertex is the time where the speed is the highest
at about t=10, the speed is at its max
Answer:
y = 2
Step-by-step explanation:
Given
y + (4 - 2y) = 2 ← remove parenthesis on left side
y + 4 - 2y = 2, that is
- y + 4 = 2 ( subtract 4 from both sides )
- y = - 2 ( multiply both sides by - 1 )
y = 2
An extraneous solution doesn't belong to the domain.
Answer:
2x^2-8x
Step-by-step explanation:
you distribute 2x to each of the terms nd u add the degree of the x
Answer:
Step-by-step explanation:
1) a variable term contains a variable. If x is a variable
5x is an example of a variable therm
2) a constant therm is not a variable
3 is an example
3) for example when a number multiply a sum or a difference between a constant and a variable
Example:
2(x-3) = 5(x+4)
4) one solution: only if x is equal to 0 the equation is true
5) no solution: the equation can’t be true for ever value of the variable
6) infinite solutions: the equation is ever true for every value of the variable
