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Gemiola [76]
2 years ago
8

How do you determine whether or not the paired t test is appropriate for a two-sample hypothesis?

Mathematics
1 answer:
Nat2105 [25]2 years ago
7 0

How to determine whether or not the paired t test is appropriate for a two-sample hypothesis is: The  two samples are independent.

<h3>What is Two-sample hypothesis?</h3>

Two-sample hypothesis can be defined as  a test that is conducted on two samples  so as to determine whether the two samples are independent.

A  paired t-test is appropriate when the scores are of  equal subject or  equal variances.

Therefore how to determine whether or not the paired t test is appropriate for a two-sample hypothesis is: The  two samples are independent.

Learn more about Two-sample hypothesis here:brainly.com/question/4232174

#SPJ1

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Please help me with this question
kramer

Answer:

1. 1 1/2 feet

2. 0.46

3a. 0.62 I'm not sure if this one's correct, it's worded weird

3b. -3.43

3c. 0.14

3d. -0.481

4 0
3 years ago
Please help i’ll give brainliest!!! thanks
Y_Kistochka [10]

Answer:

<h2>The Yangtze River</h2>

<em>Hope that helps! :)</em>

<em></em>

<em>-Aphrodite</em>

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Graph the equation y=x+7
Otrada [13]
HERE IT IS!!!


I HOPE THIS IS GOOD ENOUGH

8 0
3 years ago
Find value of n. 5/16=n/80
Viefleur [7K]
5/16 = n/80
bring 80 over to the other side to leave n alone. 80 then gets a multiplication sign in front of it.
5/16 x 80=n
5/16=0.3125
0.3125x80=25
n=25
hope this helps
3 0
3 years ago
Given: ∆AMK, MP ⊥ AK , MP = 10 m∠A = 72º, m∠PMK = 50° Find AM, MK, AK
mina [271]

Answer:

Step-by-step explanation:

The diagram of triangle AMK is shown on the attached photo. To determine AM, we would apply trigonometric ratio since triangle AMP is a right angle triangle.

Sin# = opposite/hypotenuse

Sin 72 = 10/AM

AMSin72 = 10

AM = 10/Sin72 = 10/0.9511

AM = 10.51

To determine MK,

Cos# = adjacent/hypotenuse

Cos 50 = 10/MK

MKCos50 = 10

MK = 10/Cos50 = 10/0.6428

MK = 15.6

AK = AP + KP

Tan# = opposite/adjacent

Tan 72 = 10/AP

AP tan 72 = 10

AP =10/tan72 = 10/ 3.0777 = 3.25

Tan 50 = KP/10

KP = 10tan50

KP= 10× 1.1918 = 11.918

Therefore,

AK = 3.25 + 11.918 = 15.168

3 0
3 years ago
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