3 years ago

Passes through (4 -7) and has vertex (1 -6) in vertex form. I need it quickly, please!!!

Mathematics

1 answer:

cupoosta [38]3 years ago

8 0

Wait a minute - sorry I misunderstood the question lol

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Answer:

$\Large \boxed{\sf\ \ (0,-9) \ \ }$

Step-by-step explanation:

Hello,

We know that when the parabola equation is

$y=a(x-h)^2+k$

the vertex is (h,k) and the focus is

$(h,k+\dfrac{1}{4a})$

Here, the equation is

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So,

$k+\dfrac{1}{4a}=-6-\dfrac{12}{4}=-6-3=-9$

Then, the focus is

$\large \boxed{\sf\ \ (0,-9) \ \ }$

I attached the graph, included the focus so that you can see it :-)

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