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avanturin [10]
1 year ago
13

-9x=15-3y perpendicular

Mathematics
1 answer:
aliya0001 [1]1 year ago
4 0

The linear function that is perpendicular to -9x = 15 - 3y has a slope of -1/3.

<h3>What is the question?</h3>

The question is missing in this problem, and I also did not find any problem similar to this on a search engine, hence we are going to suppose that is asks the slope of a line perpendicular to the one given.

<h3>What is a linear function?</h3>

A linear function is modeled by:

y = mx + b

In which:

  • m is the slope, which is the rate of change, that is, by how much y changes when x changes by 1.
  • b is the y-intercept, which is the value of y when x = 0, and can also be interpreted as the initial value of the function.

If two linear functions are perpendicular, the multiplication of their slopes is of -1.

In this problem, the equation is:

-9x = 15 - 3y

3y = 9x + 15

y = 3x + 5.

The slope is of 3, hence the slope of the perpendicular line is found as follows:

3m = -1 -> m = -1/3.

More can be learned about linear function concepts at brainly.com/question/24808124

#SPJ1

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4 years ago
What are the me and you
kobusy [5.1K]

Complete question:

What are the x- and y- coordinates of point E, which partitions the directed line segment from A\:(- 4,\:9) \:to\: B\:(2,\:- 3) into a ratio of 1 : 2.

Answer:

(C) (-2,5)

Step-by-step explanation:

x = (\dfrac{m}{m+n}) (x_2-x_1) + x_1\\\\y = (\dfrac{m}{m+n}) (y_2-y_1) + y_1

(x_1,y_1)=(- 4,\:9),(x_2,y_2)=B\:(2,\:- 3)

m=1, n=2

x = \left(\dfrac{1}{1+2}\right) (2-(-4)) + (-4)\\=\left(\dfrac{1}{3}\right) (2+4)-4\\=\left(\dfrac{6}{3}\right)-4=2-4\\x=-2

y = \left(\dfrac{1}{1+2}\right) (-3-9) + 9\\=\left(\dfrac{1}{3}\right) (-12)+9\\=\left(-\dfrac{12}{3}\right)+9=-4+9\\y=5

The x- and y-coordinates of the point E is (-2,5)

4 0
3 years ago
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