What is the solution to w - 9 = 15? 24 6 23 5
2 answers:
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<u><em>Answer:</em></u>
Area of the polygon = 59 in²
<u><em>Explanation:</em></u>
From the given diagram, we can note that the given polygon is composed of an upper triangle, a side triangle and a rectangle
<u>Therefore:</u>
Area of polygon =
area of upper triangle + area of side triangle + area of rectangle
<u>1- getting the area of the upper triangle:</u>
<u>We have:</u>
base of triangle = 7 in
height of triangle = 6 in
<u>Therefore:</u>
Area of upper triangle = in²
<u>2- getting the area of the side triangle:</u>
<u>We have:</u>
base of triangle = 4 in
height of triangle = 5 in
<u>Therefore:</u>
Area of upper triangle = in²
<u>3- getting the area of the rectangle:</u>
<u>We have:</u>
length of rectangle = 7 in
width of rectangle = 4 in
<u>Therefore:</u>
Area of rectangle = length x width = 7 x 4 = 28 in²
<u>4- getting the total area of the polygon:</u>
Area of polygon =
area of upper triangle + area of side triangle + area of rectangle
<u>Therefore:</u>
Area of polygon = 21 + 10 + 28 = 59 in²
Hope this helps :)
Answer: See the figure attached.
Step-by-step explanation:
Observe the figure attached. The vertices of the triangle ABC have the following coordinates:
A(2,5); B(6,2) and C(3,-5)
To graph the image (in this case we can identify it as A'B'C'), you must use the rule →
.
Then, you have to subtract 6 units from the x-coordinate of each vertex and subtract 4 units from the y-coordinate of each vertex.
Therefore, you get:
Vertex A'→
Vertex B'→
Vertex C'→
Having the vertices of the image A'B'C', you can graph it (See the figure attached).
