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1 year ago

Fossil fuels are considered to be resources because they are consumed _ than they form.

1 answer:

8 0

Fossil fuels are formed by the deposition of organic matter. It is a nonrenewable resource as they deplete faster as they are produced. Thus, option B is correct.

<h3>What is non-renewable resources?</h3><h3 />

A non-renewable resource is exhaustible and takes a longer time to get produced as they include the accumulation of organic matter over thousands of years.

Fossil fuels take a very long time to get replenished and have a slower rate of formation as compared to consumption. It includes petrol, coal, diesel, natural gases, etc.

Therefore, option B. nonrenewable and far faster are the correct blanks.

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What is the force of a 3kg skateboard accelerating at a rate of 4m/s?

Sholpan [36]

To times 4 and 3 together for mass and acceleration then your answer would be 12, So Force= 12

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3 years ago

For each reaction, find the value of ΔSo. Report the value with the appropriate sign. (a) 3 NO2(g) + H2O(l) → 2 HNO3(l) + NO(g)

aev [14]

Answer:

ΔS° = -268.13 J/K

Explanation:

Let's consider the following balanced equation.

3 NO₂(g) + H₂O(l) → 2 HNO₃(l) + NO(g)

We can calculate the standard entropy change of a reaction (ΔS°) using the following expression:

ΔS° = ∑np.Sp° - ∑nr.Sr°

where,

ni are the moles of reactants and products

Si are the standard molar entropies of reactants and products

ΔS° = [2 mol × S°(HNO₃(l)) + 1 mol × S°(NO(g))] - [3 mol × S°(NO₂(g)) + 1 mol × S°(H₂O(l))]

ΔS° = [2 mol × 155.6 J/K.mol + 1 mol × 210.76 J/K.mol] - [3 mol × 240.06 J/K.mol + 1 mol × 69.91 J/k.mol]

ΔS° = -268.13 J/K

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3 years ago

List down two applications of isotopes

Sidana [21]

Answer:

Give any two application for isotopes

Isotopes of iodine are used for radiotherapy in treatment of hyperthyroidism, cancer, etc.

Uranium, Radium, Polonium isotopes are used in atomic reactors.

Cobalt isotopes are used for irradiation of food products.

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3 years ago

Read 2 more answers

choose any bases that will selectively deprotonate the above acid, that is, any bases that will favor the formation of products.

Zanzabum

In order to deprotonate an acid, we must remove protons in order to achieve a more stable conjugate base. For this example, we can use the relationship between carboxylic acid and hydroxide.

Deprotonation is the removal of a proton from a specific type of acid in reaction to its coming into contact with a strong base. The compound formed from this reaction is known as the conjugate base of that acid. The opposite process is also possible and is when a proton is added to a special kind of base. This is a process referred to as protonation, which forms the conjugate acid of that base.

For the example we have chosen to give, the conjugate base is the carboxylate salt. This would be the compound formed by the deprotonated carboxylic acid. The base in question was strong enough to deprotonate the acid due to the greater stability offered as a conjugated base.

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2 years ago

Which one of the following metallic element is liquid are room temperature

cricket20 [7]

Answer:

The only liquid elements that can melt at standard temperature and pressure are bromine (Br) and mercury (Hg).

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3 years ago

Fossil fuels are considered to be __________ resources because they are consumed ___________ than they form.

Fossil fuels are considered to be resources because they are consumed _ than they form.