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2 years ago

choose any bases that will selectively deprotonate the above acid, that is, any bases that will favor the formation of products.

1 answer:

8 0

In order to deprotonate an acid, we must remove protons in order to achieve a more stable conjugate base. For this example, we can use the relationship between carboxylic acid and hydroxide.

Deprotonation is the removal of a proton from a specific type of acid in reaction to its coming into contact with a strong base. The compound formed from this reaction is known as the conjugate base of that acid. The opposite process is also possible and is when a proton is added to a special kind of base. This is a process referred to as protonation, which forms the conjugate acid of that base.

For the example we have chosen to give, the conjugate base is the carboxylate salt. This would be the compound formed by the deprotonated carboxylic acid. The base in question was strong enough to deprotonate the acid due to the greater stability offered as a conjugated base.

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3 years ago

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What kind of state is a roller coasters are the best use of Newton's laws of motion

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I am slightly unsure on the question, but if you are asking what kind of "statement" is "r<em>oller coasters are the best use of Newton's laws of motion</em>" then the following should answer your question:

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An opinion.

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3 years ago

How do the nuclei of different isotopes of an element vary?

Simora [160]

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Explanation:

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2.duetrium

3.tritium

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3 years ago

Calculate the frequency of a wave with a wavelength of 5.62 x 1010 m. (first convert m to nm)

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Answer:

f = 0.534×10⁻² Hz

Explanation:

Given data:

Frequency of wave= ?

Wavelength of wave = 5.62×10¹⁰ m

Solution:

Formula:

Speed of wave = wavelength × frequency

Speed of wave = 3×10¹⁷ nm/s

λ = 5.62×10¹⁰m×10⁹ nm/1 m = 5.62×10¹⁹ nm

Now we will put the values in formula.

3×10¹⁷ nm/s = 5.62×10¹⁹ nm × f

f = 3×10¹⁷ nm/s / 5.62×10¹⁹ nm

f = 0.534×10⁻² s⁻¹ or

f = 0.534×10⁻² Hz

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