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melisa1 [442]
3 years ago
12

You use 50.00 mL of a 12.0 M solution of HCl solution to make a 500.00 mL solution. What is the concentration of the new solutio

n? *
Chemistry
1 answer:
Alexandra [31]3 years ago
6 0

Answer:

1.2 M

Explanation:

If you use the dilution equation (M1V1=M2V2), you end up with (50)(12)=(500)(M2), and when you solve for M2 you get 1.2 M.

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Does anyone know what Hydrogen's oxidation state would be if it was acting as an anion non-metal?
Ilia_Sergeevich [38]

Answer:

yeah,The oxidation state of an atom does not represent the "real" charge on that atom, or any other actual atomic property.Hydrogen has OS = +1, but adopts −1 when bonded as a hydride to metals or metalloids. Oxygen in compounds has OS = −2. This set of postulates covers .

Explanation:

3 0
3 years ago
What is the formula for the compound by calcium ions and chloride ions?
dimaraw [331]
To find the ratio of the the combination for the ion, write the charge of the cation as the subscript for the anion, and the charge of the anion as the subscript of the cation. This will make the charges effectively cancel and you will be left with a neutral ionic compound. Remember, that an ionic compound is made up of a metal and a nonmetal.
For Ca2+ and Cl-, you will get the neutral compound to be CaCl₂.
8 0
4 years ago
A student is adding DI water to a volumetric flask to make a 50% solution. Unfortunately, he was not paying attention and filled
dalvyx [7]

Answer:

His results will be skewed because there was more water than stock solution. Which would cause the percentage solution to be less than 50% therefore the density would be less than the actual value.

Explanation:

The solution will have percentage less than that of 50%. Therefore the density would be less than the actual value.

Suppose there should be 50 mL of the solution, and he added 60 mL. So 10 mL of the solution is added more.

Suppose the mass of the solute is m.

Originally, the density is = $\frac{m}{50}$     \left(\frac{\text{mass}}{\text{volume}}\right)

Now after adding extra 10 mL , the density becomes $\frac{m}{60}$.

Therefore, $\frac{m}{50}>\frac{m}{60}$

So the density decreases when we add more solution.

4 0
3 years ago
Answer with explanation
creativ13 [48]
The answer should be:

KOH (aq) + HCl (aq) --> KCl (aq) + H20 (l).

KOH is a base, because OH can accept a H+.
HCl is an acid because it can donate a H+.

In general, bases are : OH-, and acids are : H+.


8 0
3 years ago
Consider the following reaction where Kc = 34.5 at 1150 K:2SO2(g) + O2(g) 2SO3(g)A reaction mixture was found to contain 4.77×10
sukhopar [10]

Answer:

Explanation:

[ so₃] = 4.37 x 10⁻²

[so₂] = 4.77 x 10⁻²

[ o₂] = 4.55 x 10⁻²

Qc = (4.37)²x10⁻⁴ /(4.77)².(4.55) x 10⁻⁶ =18.44

Qc is less than Kc hence in order to reach equilibrium more of so₃ will be produced . Statement 1 is true.

Kc is always constant . Statement 2 is false.

Statement 3 is false because statement 1 is true.

Qc Is smaller than Kc . So statement 4 is false.

The reaction is not in equilibrium. Statement 5 is false.

3 0
4 years ago
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