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Grace [21]
3 years ago
10

Identify each energy exchange as primarily heat or work and determine whether the sign of δe is positive or negative for the sys

tem.
a. sweat evaporates from skin, cooling the skin. (the evaporating sweat is the system.)
b. a balloon expands against an external pressure. (the contents of the balloon is the system.)
c. an aqueous chemical reaction mixture is warmed with an external flame. (the reaction mixture is the system.)
Chemistry
2 answers:
goldenfox [79]3 years ago
7 0
A. Heat. Positive as the sweat gains heat to evaporate.

B. Work. Negative as the balloon does work to expand.

C. Heat. Positive as heat is transferred to the mixture to warm it up.
Sonbull [250]3 years ago
6 0

Heat is released in an exothermic reaction and heat is absorbed in an endothermic reaction.  

Heat is negative for an exothermic reaction and it is positive for an exothermic reaction.  

Work done by a system is positive and work done on the system is negative.  

a. The evaporating sweat is the system. Here the sweat absorbs heat to make the phase transition from liquid water to vapor. The reaction is endothermic and the heat is positive.

b. The balloon (system) does work to expand against an external pressure. As the work is done by the system it is positive.

c. As the chemical reaction is warmed it has absorbed heat. The reaction is endothermic and the heat is positive.

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Urea, (NH2)2CO, is a product of metabolism of proteins. An aqueous solution is 37.2% urea by mass and has a density of 1.032 g/m
Feliz [49]

Answer:

The molarity of urea in this solution is 6.39 M.

Explanation:

Molarity (M) is <em>the number of moles of solute in 1 L of solution</em>;  that is

molarity = moles of solute ÷ liters of solution

To calculate the molality, we need to know the number of moles of urea and the volume of solution in liters. We assume 100 grams of solution.

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4 0
3 years ago
2. A quantity of 1.922g of methanol (CH3OH) was burned in a constant-volume
Cerrena [4.2K]
Mass of methanol (CH3OH) = 1.922 g
Change in Temperature (t) = 4.20°C
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qcal = Ccalt
Where, qcal = heat of reaction
Ccal = heat capacity of calorimeter
t = change in temperature of the sample
Now, let’s calculate qcal:
qcal = (10.4 kJ/°C)(4.20°C)
= 43.68 kJ
Always qsys = qcal + qrxn = 0,
qrxn = -43.68 kJ
The heat change of the reaction is - 43.68 kJ which is the heat released by the combustion of 1.922 g of CH3OH. Therefore, the conversion factor is:
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