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Oduvanchick [21]
1 year ago
7

One freezer costs $623.95 and uses 90 kilowatt hours (kwh) of electricity each month. A second freezer costs $500 and uses 100 k

wh of electricity each month. The expected life of each freezer is 12 years. What is the minimum electric rate in cents per kwh for which the 12-year total cost (purchase price + electricity costs) will be less for the first freezer?

Mathematics
1 answer:
lutik1710 [3]1 year ago
8 0

The minimum electric rate in cents per kwh for which the 12-year total cost will be less for the first freezer is 8.61 cents

<h3>How to calculate the rate?</h3>

Let x =  minimum electric rate (Cents/kWh)

Total months in 12 years is 12*12 = 144 m

1st freezer

Total cost over 12 years is

623.95 (cost) + (90 kWh/m)*(144 m)(x/100 $/kWh)

= 623.95 + 129.6x

2nd freezer

Total cost over 12 years is

500 + 100*144*(x/100)

= 500 + 144x

For the 1st freezer to cost less over 12 years,

623.95 + 129.6x < 500 + 144x

123.95 < 14.4x

8.61 < x

The minimum rate is 8.61 cents per kWh

Learn more about rate on:

brainly.com/question/25537936

#SPJ1

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Answer:

The general solution of   cos x = cos(\frac{\pi }{6})   is  

                                                x = 2nπ±\frac{\pi }{6}

The general solution values  

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Step-by-step explanation:

Explanation:-

Given equation is  

                              2cosx-\sqrt{3} =0  for 0

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Dividing '2' on both sides, we get

                             cos x =\frac{\sqrt{3} }{2}

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<em>General solution of cos θ = cos ∝ is θ = 2nπ±∝</em>

<em>Now The general solution of   </em>cos x = cos(\frac{\pi }{6})<em>   is  </em>

<em>                                                 x = 2nπ±</em>\frac{\pi }{6}<em></em>

put n=0

x = - \frac{\pi }{6}  and x = \frac{\pi }{6}

Put n=1  

x = 2\pi +\frac{\pi }{6} = \frac{13\pi }{6}

x = 2\pi -\frac{\pi }{6} = \frac{11\pi }{6}

put n=2

x = 4\pi +\frac{\pi }{6} = \frac{25\pi }{6}

x = 4\pi -\frac{\pi }{6} = \frac{23\pi }{6}

And so on

But given 0 < x< 2π

The general solution values  

                                 x = - \frac{\pi }{6}  and x = \frac{\pi }{6}

                               

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