All categories

3 years ago

Line k has a slope of 2/3. If line m is parallel to line k, then it has a slope of

Mathematics

1 answer:

puteri [66]3 years ago

6 0

Answer:

Line M would also have a slope of 2/3.

Step-by-step explanation:

When two line are parallel that means that they will never intersect.

In order for two lines to avoid intersection they would have to be at the same slope.

Since lines K and line M are parallel to each other they have to have the same slope.

You might be interested in

Use the vertical line test to determine if the relation {(–6, –2), (–2, 6), (0, 3), (3, 5)} is a function

hammer [34]

Answer: Its a function

Step-by-step explanation:

6 0

3 years ago

Amy is cooking muffins the recipe calls for 3 5/7 cups of sugar. She has already put in 2 1/10 cups. How many more cups does she

nikitadnepr [17]

Answer:

1.61428571429

Step-by-step explanation:

That would be about 1.62. You do 3 5/7-2 1/10. That would equal to 1.61428571429.

6 0

3 years ago

The difference of the degrees of the polynomials p(x) = 3x2y2 + 5xy? - x6 and q(x) = 3x5 - 4x3 + 2 is

svet-max [94.6K]

Answer:

The difference of the degrees of the polynomials p (x) and q (x) is 1.

Step-by-step explanation:

A polynomial function is made up of two or more algebraic terms, such as p (x), p (x, y) or p (x, y, z) and so on.

The polynomial’s degree is the highest exponent or power of the variable in the polynomial function.

The polynomials provided are:

$p(x) = 3x^{2}y^{2} + 5xy - x^{6}\\\\q(x) = 3x^{5} - 4x^{3} + 2$

The degree of polynomial p (x) is:

$\text{deg}\ p (x)=6$

The degree of polynomial q (x) is:

$\text{deg}\ q (x)=5$

The difference of the degrees of the polynomials p (x) and q (x) is:

$\text{deg}\ p(x)-\text{deg}\ q(x)=6-5=1$

Thus, the difference of the degrees of the polynomials p (x) and q (x) is 1.

6 0

3 years ago

(05.03)(picture included)Sue has to cut her grandma's grass this weekend and wants to know exactly how much area she will be cut

kifflom [539]

Answer:

Solution given:

BD=35ft

AC=43ft

AB=8ft

EF=33-8=25ft

AE=26ft

Now

area of right angled triangle ∆AEF

=½(EF*AE)=½(25×25)=312.5ft²

area of parallel trapezoid=½AB(BD+AC)

=½*8(35+43)=312ft²

So

Area of polygon : 312.5+312=624.5ft² is a required answer.

3 0

2 years ago

Read 2 more answers

10. Does the function represent a linear or nonlinear function? For 10 or 11

solniwko [45]

I believe their both linear because their in the correct form

4 0

2 years ago

Read 2 more answers