Answer:
The top of the ladder go down by 0.15 m.
Explanation:
Here we have right angled triangle.
Hypotenuse = 4.6 m
Bottom angle = 66º
Length from ladder bottom to wall bottom = 4.6 cos66 = 1.87 m
Length from ladder top to wall bottom = 4.6 sin66 = 4.20 m
New length from ladder bottom to wall bottom = 1.87 + 0.31 = 2.18 m
By Pythagoras theorem
New length from ladder top to wall bottom is given by
Distance the top of the ladder go down = 4.20 - 4.05 = 0.15 m
To solve this problem we will use the concepts given by the rotational kinetic energy which describes the energy in a body product of its moment of inertia and its angular velocity, mathematically this is given as,
Where,
I = Moment of Inertia
= Angular Velocity
Replacing with our values we have that,
Therefore the rotational energy is 178.125J
Answer:
2917.4 m/s
Explanation:
From the question given above, the following data were:
Gravitational acceleration of the Moon (g) = 0.25 times the gravitational acceleration of the earth
Radius (r) of the Moon = 1737 Km
Escape velocity (v) =?
Next, we shall determine the gravitational acceleration of the Moon. This can be obtained as follow:
Gravitational acceleration of the earth = 9.8 m/s²
Gravitational acceleration of the Moon (g) = 0.25 times the gravitational acceleration of the earth
= 0.25 × 9.8 = 2.45 m/s²
Next, we shall convert 1737 Km to metres (m). This can be obtained as follow:
1 Km = 1000 m
Therefore,
1737 Km = 1737 Km × 1000 m / 1 Km
1737 Km = 1737000 m
Thus, 1737 Km is equivalent to 1737000 m
Finally, we shall determine the escape velocity of the rocket as shown below:
Gravitational acceleration of the Moon (g) = 2.45 m/s²
Radius (r) of the moon = 1737000 m
Escape velocity (v) =?
v = √2gr
v = √(2 × 2.45 × 1737000)
v = √8511300
v = 2917.4 m/s
Thus, the escape velocity is 2917.4 m/s
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