The air going into the tyre was warmed up by the pumping. What effect will this have on the motion of Gad molecules in the air i
1 answer:
You might be interested in
Answer:
The lighter frog goes higher than the heavier frog.
The lighter frog is moving faster than the heavier frog
Explanation:
If both frogs have the same kinetic energy when they leave the ground, the following equality applies:
Now, if the only force acting on the frogs is gravity, when they reach to the maximum height, we can apply the following kinematic equation:
When h= hmax, the object comes momentarily to an stop, so vf =0
Solving for hmax:
As the lighter frog, in order to have the same kinetic energy than the heavier one, has a greater initial velocity, it will go higher than the other.
As a consequence of both having the same kinetic energy, the lighter frog will be moving faster than the heavier frog.
Answer:
Explanation:
<u>Given:</u>
Mass = m = 200,000 kg
Vertical Distance = h = 120 m
Speed = v = 14 m/s
Acceleration due to gravity = g = 10 m/s²
<u>Required:</u>
1) Gravitational Potential Energy = P.E = ?
2) Kinetic Energy = K.E. = ?
<u>Formula:</u>
1) P.E. = mgh
2) K.E. =
<u>Solution:</u>
1) P.E. = (200,000)(10)(120)
P.E. = 240,000,000 Joules
P.E. = 240 Mega Joules
P.E. = 240 MJ
2) K.E. = 1/2 (200000)(14)^2
K.E. = (100000)(196)
K.E. = 19,600,000 Joules
K.E. = 19.6 MJ
Hope this helped!
<h3>~AH1807</h3>