Answer:
No, the car will not make it to the top of the hill.
Explanation:
Let ΔX be how long the slope of the hill is, Δx be how far the car will travel along the slope of the hill, Ф be the angle the slope of the hill makes with the horizontal(bottom of the hill), ki be the kinetic energy of the car at the bottom of the hill and vi be the velocity of the car at the bottom of the hill and kf be the kinetic energy of the car when it stop moving at vf.
Since Ф is the angle between the horizontal and the slope, the relationship between the angle and the slope and the height of the hill is given by
sinФ = 12/ΔX
Which gives you the slope as
ΔX = 12/sinФ
Therefore for the car to reach the top of the hill it will have to travel ΔX.
Ignoring friction the total work done is given by
W = ΔK
W = (kf - ki)
Since the car will come to a stop, kf = 0 J
W = -ki
m×g×sinФ×Δx = 1/2×m×vi^2
(9.8)×sinФ×Δx = 1/2×(10)^2
sinФΔx = 5.1
Δx = 5.1/sinФ
ΔX>>Δx Ф ∈ (0° , 90°)
(Note that the maximum angle Ф is 90° because the slope of a hill can never be greater ≥ 90° because that would then mean the car cannot travel uphill.)
Since the car can never travel the distance of the slope, it can never make it to the top of the hill.
Answer:
y maximum 3.54 m, value X 2.35 m
Explanation:
We have a projectile launch problem, let's calculate the maximum height of the projectile, where the vertical speed must be zero
Vyf² = Vyo² - 2g (Y-Yo)
Where Yo is the initial height of the ramp 1.5 m
0 = Vyo² -2g (Y-Yo)
Y-Yo = Voy² / 2g
Y = Yo + Voy² / 2g
Let's calculate the velocity components using trigonometry
Voy = vo without T
Vox = Vo cost
Voy = 7.3 sin 60
Vox = 7.3 cos 60
Voy = 6.32 m / s
Vox = 3.65 m / s
Let's calculate the maximum height
Y = 1.5 +6.32²/2 9.8
Y = 3.54 m
This is the maximum height from the ground
b) They ask us for the position of this point horizontally, we can calculate it looking for the time it took for the skateboarder to reach the highest point
Vfy = Voy - gt
0 = Voy - gt
t = Voy / g
t = 6.32 / 9.8
t = 0.645 s
Since there is no acceleration on the x-axis, we have a uniform movement, we can calculate the distance for this time
X = Vox t
X = 3.65 0.645
X= 2.35 m
Answer:
The example of the center of the gravity is the middle of a seesaw
Explanation:
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<span>An object roating at one revokution per second has an angular velocity of 360 degrees per second or 2pi radians per second. This is found by taking the number of revolutions over a period of time and than dividing by the chosen period of time to get the velocity. There are 360 degrees or 2pi radians in one revolution.</span>
