We are given the following function and want to find the y-intercept:
Just substitute the value x=0 into the equation to find the value of the y-intercept:
Simplify
Simplify again
Since the value of f(x), or y, when x=0 is 66, the y-intercept of this function is 66.
Let me know if you need any clarifications, thanks!
~ Padoru
Answer:
8 +
Step-by-step explanation:
From the phrase, the <em>answer</em> is smaller(less) by 8 when compared(equal (=)) to quotient of 5 and w ...
So:
Answer - 8 = quotient of 5 and w
Here, quotient is the whole number from a <em>division</em>. The division here is
Therefore,
Answer - 8 =
Answer = 8 +
Hence the phrase into algebraic expression is 8 +
Answer:
80 m^2
Step-by-step explanation:
The given information lets you write two equations involving length (x) and width (y).
The second of these equations simplifies to another linear equation, giving a system of linear equations easily solved.
xy +y +2x + 2 -xy = 30
2x +y = 28 . . . . . . . subtract 2
Dividing the first equation by 2 gives
x +y = 18
and subtracting this from the above equation gives ...
(2x +y) -(x +y) = 28 -18
x = 10
Then
y = 18 -10 = 8
The area of the original rectangle is xy = 10·8 = 80 m^2.
The statements that are true about the intervals of the continuous function are Options 2, 4 and 5
Looking at the values given, the intervals which satisfies the condition are known to be:
f(x)<=0 over the interval [0,2]
f(x)>0 over the interval (-2,0)
f(x)>=0 over the interval [2,∞)
Because:
Since the table with x and f(x) values, we have to examine analyze the table and see the each option that is in line with f(x) or not .
Examine the values of x that is from -3 to 3, the f(x) values are both positive and negative . hence f(x)>0 is false over the interval (-∞,3)
Looking at the the interval from 0 to 2, the f(x) values are 0 and negative. Hence, f(x)<=0 over the interval [0,2]
When you look over the interval (-1,1), the f(x) values are said to be both positive and negative and as such, f(x)<0 is false over the interval (-1,1)
When you look at the interval (-2,0) , the f(x) is positive and as such, f(x)>0 over the interval (-2,0)
Looking at the interval [2,∞), f(x) is positive and as such, f(x)>=0 over the interval [2,∞)
Therefore, Option 2, 4 and 5 are correct.
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