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2 years ago

Write a trinomial expression that is equivalent to (2x+5)(3x-2)

Mathematics

1 answer:

Vikentia [17]2 years ago

7 0

2x *3x =6x^2

2x*(-2)= -4x

5*3x=15x

5* (-2) =- 10

6x^2 -4x +15x -10

6x^2 + 11x -10

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There are 49 female performers in a dance recital. The ratio of men to women is 5:7. How many men are in the dance recital?

melisa1 [442]

Answer:

35 Men were in the dance recital

Step-by-step explanation:

The ratio from MEN to WOMEN is 5:7

49 female performers is 7

49/7= 7 performers

to find how many men, you would do 7*5

7*5= 35

35 Men were in the dance recital

Hope this helps and made sense!

6 0

3 years ago

Can someone please solve #8

juin [17]

Answer:

Step-by-step explanation:

2x²+7x=-3

2x²+7x+3=0

2x²+x+6x+3=0

x(2x+1)+3(2x+1)=0

(2x+1)(x+3)=0

x=-1/2,-3

so C

8 0

3 years ago

Which numerical pattern is nonlinear?

kow [346]

Answer:

I think it's the first one

Step-by-step explanation:

8 0

3 years ago

Let φ(x, y) = arctan (y/x) .

Alexandra [31]

Answer:

a) $\large F(x,y)=(-\frac{y}{x^2+y^2},\frac{x}{x^2+y^2})$

b) $\large \mathbb{R}^2-\{(0,0)\}$

c) the points of the form (x, -x) for x≠0

Step-by-step explanation:

If φ(x, y) = arctan (y/x), the vector field F = ∇φ would be

$\large F(x,y)=(\frac{\partial \phi}{\partial x},\frac{\partial \phi}{\partial y})$

On one hand we have,

$\large \frac{\partial \phi}{\partial x}=\frac{\partial arctan(y/x)}{\partial x}=\frac{-y/x^2}{1+(y/x)^2}=-\frac{y/x^2}{1+y^2/x^2}=\\\\=-\frac{y/x^2}{(x^2+y^2)/x^2}=-\frac{y}{x^2+y^2}$

On the other hand,

$\large \frac{\partial \phi}{\partial y}=\frac{\partial arctan(y/x)}{\partial y}=\frac{1/x}{1+(y/x)^2}=\frac{1/x}{1+y^2/x^2}=\\\\=\frac{1/x}{(x^2+y^2)/x^2}=\frac{x}{x^2+y^2}$

$\large F(x,y)=(-\frac{y}{x^2+y^2},\frac{x}{x^2+y^2})$

The domain of definition of F is

$\large \mathbb{R}^2-\{(0,0)\}$

i.e., all the plane X-Y except the (0,0)

Here we want to find all the points such that

$\large (-\frac{y}{x^2+y^2},\frac{x}{x^2+y^2})=(k,k)$

where k is a real number other than 0.

But this means

$\large -\frac{y}{x^2+y^2}=\frac{x}{x^2+y^2}\Rightarrow y=-x$

So, all the points in the line y = -x except (0,0) are parallel to the vector field F, that is, the points (x, -x) with x≠ 0

8 0

2 years ago

PLEASE ANSWER ASAP!

Blizzard [7]

Step-by-step explanation:

Let the length of the bridge be x

Since, triangles ADF and BCF are similar, ratio of their corresponding sides are equal.

Therefore,

60 / 144 = 40 / x

X (length of the bridge) = <u>96 m</u>

4 0

3 years ago