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AVprozaik [17]
3 years ago
6

I WILL GIVE BRAINLIEST AND 10 POINTS PLEASE HELP FAST!!!!!Solve the equation using inverse operations. Check your solutions. In

your final answer, include all of your work.
5 - 2 x y^2 = -15 solve for y
Mathematics
1 answer:
Yanka [14]3 years ago
8 0

Answer:

5-2=3

3 x <u>       </u>= 7.5^2

15 divided by 3 =5

3 x 5^2 = 15

y= 5

(hope this helps)

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A tank contains 240 liters of fluid in which 20 grams of salt is dissolved. Brine containing 1 gram of salt per liter is then pu
Novosadov [1.4K]

Answer:

A(t)=240-220e^{-\frac{t}{40}}

Step-by-step explanation:

A tank contains 240 liters of fluid in which 20 grams of salt is dissolved.

  • Volume of the tank = 240 liters
  • Initial Amount of Salt in the tank, A(0)=20 grams

Brine containing 1 gram of salt per liter is then pumped into the tank at a rate of 6 L/min

R_{in}=(concentration of salt in inflow)(input rate of fluid)

R_{in}=(1\frac{gram}{liter})( 6\frac{Liter}{min})=6\frac{gram}{min}

R_{out}=(concentration of salt in outflow)(output rate of fluid)

R_{out}=(\frac{A(t)}{240})( 6\frac{Liter}{min})\\R_{out}=\frac{A}{40}

Rate of change of the amount of salt in the tank:

\dfrac{dA}{dt}=R_{in}-R_{out}

\dfrac{dA}{dt}=6-\dfrac{A}{40}

We then solve the resulting differential equation by separation of variables.

\dfrac{dA}{dt}+\dfrac{A}{40}=6\\$The integrating factor: e^{\int \frac{1}{40}dt} =e^{\frac{t}{40}}\\$Multiplying by the integrating factor all through\\\dfrac{dA}{dt}e^{\frac{t}{40}}+\dfrac{A}{40}e^{\frac{t}{40}}=6e^{\frac{t}{40}}\\(Ae^{\frac{t}{40}})'=6e^{\frac{t}{40}}

Taking the integral of both sides

\int(Ae^{\frac{t}{40}})'=\int 6e^{\frac{t}{40}} dt\\Ae^{\frac{t}{40}}=6*40e^{\frac{t}{40}}+C, $(C a constant of integration)\\Ae^{\frac{t}{40}}=240e^{\frac{t}{40}}+C\\$Divide all through by e^{\frac{t}{40}}\\A(t)=240+Ce^{-\frac{t}{40}}

Recall that when t=0, A(t)=20 (our initial condition)

20=240+Ce^{-\frac{0}{40}}\\20-240=C\\C=-220\\$Therefore, the number A(t) of grams of salt in the tank at time t\\A(t)=240-220e^{-\frac{t}{40}}

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3 years ago
Find the value for the side marked below.
olga55 [171]

Answer:

Solution given:

angle : 80°

hypotenuse:y=?

opposite=21

we have

Sin 80=\frac{opposite} {hypotenuse}=\frac{21}{y}

doing crisscrossed multiplication

we get

y=\frac{21}{Sin 80°}

<u>y=21.32</u>

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It is C hope i helped you!;)
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The probability distribution table shows the proportion of people living in the five different regions of a city there are now 4
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