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Aneli [31]
3 years ago
13

Which equation is an identity

Mathematics
1 answer:
lubasha [3.4K]3 years ago
8 0
This is from google:
An equation that is true for every value of the variable is an identity. The equation 2x = 2x is an identity.
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Find the x !<br> please hurry! Thank you!
wolverine [178]

Step-by-step explanation:

2x+98=180° (angles in straight line )

2x=180-98

x=2/2

x=1

6 0
2 years ago
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A drain must be installed with a grade of 1/10 in. of vertical drop per foot of horizontal run. How much of a drop will there be
professor190 [17]

Answer:

1/10 x 58 =5.8 if they want it in fraction its 4/5

6 0
2 years ago
honestly i'm ready to give up, I need help but nobody's helping and it's extremely stressful so could someone please help. and n
Keith_Richards [23]

Answer:

b-d-e

Step-by-step explanation:

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7 0
3 years ago
There were 3 bananas, 4 apples, and 3 oranges in a basket. What is the probability that Ace will pick a banana from the basket?
Jlenok [28]

0.3 or 30%. The probability that Ace pick a banana from a basket that content others fruits is 0.3.

The key to solve this problem is using the equation of probability P(A)=\frac{n(A)}{n} where n(A) the numbers of favorables outcomes and n the numbers of possible outcomes.

There are in the basket 10 fruits in total (3 bananas + 4 apples + 3 oranges = 10fruits). Then, extract a fruit can occur in 10 ways, this is n. There is only 3 bananas in the basket, so the fruit that ACE will pick be a banana can occur in 3 ways out of 10,  so 3 is n(A).

Solving the equation:

P(A)=\frac{3}{10}=0.3

5 0
4 years ago
Frankie solved the math problem below. Find the error in Frankie's work and explain it in words, using math language. 2 1/3 - 1
HACTEHA [7]

Given:

The expression is

2\dfrac{1}{3}-1\dfrac{2}{5}

To find:

The error in Frankie's work.

Solution:

We need to simplify 2\dfrac{1}{3}-1\dfrac{2}{5}, so

2\dfrac{1}{3}=2\dfrac{1}{3}\times \dfrac{5}{5}

2\dfrac{1}{3}=2\dfrac{5}{15}

and,

1\dfrac{2}{5}=-1\dfrac{2}{5}\times \dfrac{3}{3}

1\dfrac{2}{5}=-1\dfrac{6}{15}

Now,

2\dfrac{1}{3}-1\dfrac{2}{5}=2\dfrac{5}{15}-1\dfrac{6}{15}

2\dfrac{1}{3}-1\dfrac{2}{5}=(2+\dfrac{5}{15})-(1+\dfrac{6}{15})

2\dfrac{1}{3}-1\dfrac{2}{5}=2+\dfrac{5}{15}-1-\dfrac{6}{15}

2\dfrac{1}{3}-1\dfrac{2}{5}=1-\dfrac{1}{15}

2\dfrac{1}{3}-1\dfrac{2}{5}=\dfrac{14}{15}

Therefore, there is error in Frankie's last step. In that step, he did not subtract the mixed fraction correctly.

8 0
3 years ago
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