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3 years ago

9

The box plot represents the number of minutes customers spend on hold when calling a company.

1 answer:

saveliy_v [14]3 years ago

4 0

Answer:

6

Step-by-step explanation:

By the diagram you can see that the upper quartile is 6. Also this answer was calculated and checked!

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Plz help me with this

Nitella [24]

Answer: C) y ≥ 3x - 2; $y\leq \dfrac{1}{2}x+3$

<u>Step-by-step explanation:</u>

Blue line:

y-intercept (b) = -2

slope (m) is 3 up, 1 right = 3

shading is above

⇒ y ≥ 3x - 2

Yellow line:

y-intercept (b) = 3

slope (m) is 1 up, 2 right = $\dfrac{1}{2}$

shading is below

$\implies \bold{y\leq \dfrac{1}{2}x+3}$

8 0

4 years ago

The circumference of a circle of radius r is given by the polynomial 2 pi r2πr, where piπ is an irrational number. For an appro

Degger [83]

To find the circumference you use c = pi d. Radius * 2 = Diameter
c = 3.14(36)
c = 113.04 in. square.

6 0

4 years ago

our friend is graphing the point (1, 7). Her first step is to start at the origin and go right 7 spaces. Is her method correct?

balandron [24]

No because she needs to go over 1 space from the origin and up 7 spaces to correctly graph it

6 0

4 years ago

Read 2 more answers

Simpifly -3x+12x slide the answers you already know my guy

zaharov [31]

answer:

9x

Step-by-step explanation:

there both like terms with means you can just and and subtract them.

7 0

2 years ago

The U.S. Energy Information Administration (US EIA) reported that the average price for a gallon of regular gasoline is $2.94. T

Anit [1.1K]

Answer:

a) 25

b) 67

c) 97

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.95}{2} = 0.025$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.025 = 0.975$ , so $z = 1.96$

Now, find the margin of error M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample. In this problem, $\sigma = 0.25$

(a) The desired margin of error is $0.10.

This is n when M = 0.1. So

$M = z*\frac{\sigma}{\sqrt{n}}$

$0.1 = 1.96*\frac{0.25}{\sqrt{n}}$

$0.1\sqrt{n} = 1.96*0.25$

$\sqrt{n} = \frac{19.6*0.25}{0.1}$

$(\sqrt{n})^{2} = (\frac{19.6*0.25}{0.1})^{2}$

$n = 24.01$

Rounding up to the nearest whole number, 25.

(b) The desired margin of error is $0.06.

This is n when M = 0.06. So

$M = z*\frac{\sigma}{\sqrt{n}}$

$0.06 = 1.96*\frac{0.25}{\sqrt{n}}$

$0.06\sqrt{n} = 1.96*0.25$

$\sqrt{n} = \frac{19.6*0.25}{0.06}$

$(\sqrt{n})^{2} = (\frac{19.6*0.25}{0.06})^{2}$

$n = 66.7$

Rounding up, 67

(c) The desired margin of error is $0.05.

This is n when M = 0.05. So

$M = z*\frac{\sigma}{\sqrt{n}}$

$0.05 = 1.96*\frac{0.25}{\sqrt{n}}$

$0.05\sqrt{n} = 1.96*0.25$

$\sqrt{n} = \frac{19.6*0.25}{0.05}$

$(\sqrt{n})^{2} = (\frac{19.6*0.25}{0.05})^{2}$

$n = 96.04$

Rounding up, 97

8 0

3 years ago