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1 year ago

Is it possible for the entropy of both a closed system and its surroundings to decrease during the process?

1 answer:

6 0

Only when heat is transferred from the system to its surroundings does a closed system suffer a decrease in entropy.

Only when heat is transferred from the system to its surroundings does a closed system suffer a decrease in entropy. Every internally reversible operation in a closed system generates entropy. Entropy remains constant in an adiabatic and internally reversible process of a closed system. Isolated systems' entropy cannot diminish.

When a system is not isolated but is in contact with its surroundings, the entropy of the open system may drop, requiring a balancing rise in the entropy of the surroundings. During a process, the entropy of an isolated system constantly increases, or in the case of a reversible process, remains constant (it never decreases).

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Answer:

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2 years ago

In a thin layer chromatography experiment, a plate of length 9.3 cm was used and a horizontal line was made at 1.45 cm above the

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Answer: The $R_f$ value is 0.664

Explanation:

Distance travelled by solvent front = (7.7-1.45)cm = 6.25 cm

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The retention factor or the $R_f$ value is defined as the ratio of distance traveled by the unknown to the distance traveled by the solvent front.

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2 years ago

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2 years ago

Ca+Cl2-->CaCl2 Then, write balanced half-reactions describing the oxidation and reduction that happen in this reaction.

kompoz [17]

Answer:

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8 0

3 years ago

What is the molarity of an aqueous solution containing 1.5 moles of calcium chloride in 2.75 L of solution? A. 0.004 M B. 0.55 M

kondor19780726 [428]

Answer:

B. 0.55 M

Explanation:

Step 1: Given data

Moles of calcium chloride (solute): 1.5 mol

Volume of solution: 2.75 M

Step 2: Calculate the molarity of the aqueous solution

The molarity is a way to express the concentration of a solution. It is equal to the quotient between the moles of solute and the liters of solution.

M = moles of solute / liters of solution

M = 1.5 mol / 2.75 L = 0.55 mol/L = 0.55 M

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2 years ago