What’s the answer to 4x(x+3) < -24

Mathematics

1 answer:

NARA [144]1 year ago

6 0

The answer to the inequality is expressed as x< 1 and x< -4

<h3>What are inequalities?</h3>

Inequalities are mathematical expressions having both sides unequal or rather not equivalent to each other.

Given the inequality;

4x (x+3) < -24

First, expand the bracket

4x² + 12x < - 24

Let's turn to quadratic inequality

4x² + 12x - 24 < 0

Factorize further

4 ( x² + 3x - 4) < 0

4 ( x² + 4x - x - 4) < 0

4 ( x(x + 4) - 1 (x + 4) ) < 0

4(x - 1) ( x + 4) < 0

expand the bracket

4x - 4 < 0

x < 1

And

4x + 16 < 0

x < -4

Thus, the answer to the inequality is expressed as x< 1 and x< -4

Learn more about inequalities here:

brainly.com/question/25275758

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Graph the function and analyze it for domain, range, continuity, increasing or decreaseing behavior, symmetry, boundedness, extr

Sunny_sXe [5.5K]

Answer:

$f(x) = 3 \cdot 0.2^x$

Step-by-step explanation:

$f(x) = 3 \cdot 0.2^x$

Domain of f: "What values of x can we plug into this equation?" This makes sense for all real numbers so the domain is $\mathbb{R}$

Range of f: "What values of f(x) can we get out of the function?" From the graph we see we can get any real number greater than 0 out of the function by choosing a suitable x-value in the domain. The range is therefore $(0, \infty)$ .

Continuity: Since the graph is one, unbroken curve (i.e. a curve that can be drawn in one movement without taking your pen off the paper). We see that "roughly speaking" the function is continuous.

Increasing or decreasing behaviour: For all x in the domain, as x increases, f(x) decreases. This means the function exhibits decreasing behaviour.

Symmetry: It is clear to see the graph of f(x) has no symmetry.

Boundedness: Looking at the graph we see it is unbounded above as when we choose negative values, the graph of f(x) explodes upwards exponentially. Choose a value of x, plug it in, next choose (x-1), plug this in and we observe $f(x-1) > f(x)$ for all x in the domain.

The function is however bounded below by 0: no value of x in the domain exists which satisfies $f(x) < 0$ .

Extrema: As far as I can tell, there are no turning points on the curve. (Is this what you mean by extrema?)

Asymptotes: Contrary to the curve's appearance, there are no vertical asymtotes for this curve. The negative-x portion of the curve is just growing so quickly it appears to look like an asymptote. There is a value of f(x) for all x<0. There is however a horizontal asymtote: $y=0$ .