Answer:
There is no unique solution to this problem.
There are infinitely many solutions to this problem.
Step-by-step explanation:
Let B denotes broccoli crop
Let S denotes spinach crop
Last year, he grew 6 tons of broccoli per acre and 9 tons of spinach per acre, for a total of 93 tons of vegetables.
Mathematically,
6B + 9S = 93 eq. 1
This year, he grew 2 tons of broccoli per acre and 3 tons of spinach per acre, for a total of 31 tons of vegetables.
Mathematically,
2B + 3S = 31
2B = 31 - 3S
B = (31 - 3S)/2 eq. 2
Substitute eq. 2 into eq. 1
6B + 9S = 93
6[(31 - 3S)/2] + 9S = 93
3(31 - 3S) + 9S = 93
93 - 9S + 9S = 93
- 9S + 9S = 93 - 93
0 = 0
Therefore, there is no unique solution to this problem.
Which means that there are infinitely many solutions to this problem.
(n/6 + 8) - 3 = 7
(n/6 + 8) - 3 + 3 = 7 + 3
n/6 + 8 - 8 = 10 - 8
n/6 = 2
(n/6)(6) = 2(6)
n = 12
The answer would be B as half of 6 is 3 and 3 x 5 is 15 , 15 x 10 is 150 :)<span />
