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Tom [10]
2 years ago
4

A student simplified (the cube root of 64 − 10 ÷ 2)(5 − 7)2 using the following steps:

Mathematics
1 answer:
Mrrafil [7]2 years ago
7 0

A) The first operation should be division but instead the student used subtraction and that's the first error made.

B) Step 4 should have been to solve the bracket to get -3(-2)². Student instead squared the 7 and as such that was the mistake.

<h3>How to use order of operations?</h3>

The acronym for the order of operations to be used here is called BODMAS. This means;

Bracket of Division Multiplication Addition Subtraction.

Thus, the first operation must be bracket and follow that order above.

A) After Step 1, the student got; (4 − 10 ÷ 2)(5 − 7)²

Now, according to BODMAS, the next step is to solve the bracket. Inside the first bracket, the first operation should be division but instead the student used subtraction and that's the first error made.

B) In step 3, the student had −3(5 − 7)²

From BODMAS, the next step in step 4 should have been to solve the bracket to get -3(-2)². Student instead squared the 7 and as such that was the mistake.

C)  (∛64 − 10 ÷ 2)(5 − 7)²

Step 1; Solve the first bracket by reducing the cube root to get;

(4 - 10 ÷ 2)(5 − 7)²

Step 2; Inside the first bracket, carry out division operation to get;

(4 - 5)(5 − 7)²

Step 3; Inside the second bracket carry out subtraction to get;

(4 - 5)(-2)²

Step 4; Square the second bracket to get'

(4 - 5)(4)

Step 5; Subtract inside the first bracket to get;

(-1)(4)

Step 6; Multiply to get;

-4

Read more about order of operations at; brainly.com/question/16788360

#SPJ1

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