I think the parent function is
y=x
X=-b/2a is the formula for finding the axis of symmetry
So x= -30/2(5)
X=-30/10
X=-3
Because the axis of symmetry is -3, we know where to place our line, and we also know that the parabola is open downwards, which means that the vertex will be maximum. To find the vertex, plug in your values with the axis of symmetry as a midway point. Plug that in for x and so you should have the following:
F(x)
Y(f(x) and y variables are interchangeable) =5(-3)^2-30(-3)+49
Solve for y(f(x))
5(-3)^2-30(-3)+49
(-3)^2=3^2
3^2*5+30*3+49
Multiply
3^2*5+90+49
Add numbers
3^2*5+139
9*5=45
45+139=184
Y=184
So, your vertex would be
(-3,184) and it would be maximum. From there you can plug in the rest of your table of values.
VX = 204
Divide by 3 to get the 2/3 , 1/3 ratio of the segments
204/3= 68
68*2= 136
VW= 136, XW= 68
Do the same for RW, RY
RW= 104 this is 2/3 of the segment. Divide by 2.
WY= 52. RY= 156
#7
Find the midpoint of each side. (0,2) (7,4) m1=(3.5,3)
(0,3) (5,0) m2=(2.5,1.5)
(5,0) (7,4) m3=(6,2)
Draw a segment from each midpoint to its opposite vertex. The point of intersection is (4,2)
Answer: total comes to 4X - 12Y + 4
Step-by-step explanation:
The total length of a line segment is the sum of the lengths of its parts.
MQ = MK + KQ . . . . . . express the relationship between the segments
15 in = 7 in + KQ . . . . . fill in the given information
(15 - 7) in = KQ . . . . . . .subtract 7 in
KQ = 8 in . . . . . . . . . . . simplify
The measurement of KQ is 8 inches.
