Answer:
Step-by-step explanation:
using the rule of exponents
= 
note that 6 = 
, then
= 
=
Answer:
like on each assignment a 90 or 100%
Step-by-step explanation:
Answer:
option D
Step-by-step explanation:
Problem
For a quadratic equation function that models the height above ground of a projectile, how do you determine the maximum height, y, and time, x , when the projectile reaches the ground
Solution
We know that the x coordinate of a quadratic function is given by:
Vx= -b/2a
And the y coordinate correspond to the maximum value of y.
Then the best options are C and D but the best option is:
D) The maximum height is a y coordinate of the vertex of the quadratic function, which occurs when x = -b/2a
The projectile reaches the ground when the height is zero. The time when this occurs is the x-intercept of the zero of the function that is farthest to the right.
Answer:
No, it is not a right triangle.
Step-by-step explanation:
If the triangle was a right triangle, then the Pythagorean Theorem states that a^2 + b^2 = c^2. Let's test it on this triangle:
13^2 + 14^2 = 365, or c^2. If this is a right triangle, c should equal 15.
However, sqrt(365) = 19.1, which is not 15. So, the triangle is not a right triangle.
