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svet-max [94.6K]
2 years ago
7

The seemingly __________ but very important goal of passing physics, and therefore maintaining a high gpa, motivated kelly to st

udy extra long hours.
Physics
1 answer:
Anastasy [175]2 years ago
6 0

The seemingly invincible but very important goal of passing physics, and therefore maintaining a high GPA, motivated Kelly to study extra long hours.

The goal of the Physics primary is to provide the scholar with a broad understanding of the bodily standards of the universe, to help them develop critical thinking and quantitative reasoning skills, to empower them to suppose creatively and critically about medical troubles and experiments, and to provide schooling.

The key to passing a physics examination is to memorize critical equations and their applications. To do so, write down the equation on one facet of a observe card and what it's used for on the other side, then go through the cards and memorize every equation.

Physics allows us to prepare the universe. It deals with basics, and enables us to look the connections among seemly disparate phenomena. Physics gives us powerful gear to help us to explicit our creativity, to peer the sector in new approaches after which to alternate it. Physics is useful.

Invincible is an American adult animated superhero television series, based on the Image Comics series.

Learn more about invincible here:- brainly.com/question/1133228

#SPJ4

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The latent heat of vaporization for water at room temperature is 2430 J/g.
alukav5142 [94]

Answer:

1)   kinectic energy=7.26*10^-^2^0J

2)  V= 2.0m/s

3)  T=3.5*10^3K

4)  The Molecules do not burn because of the presences of hydrogen bond in place

Explanation:

From the question we are told that

latent heat of vaporization for water at room temperature is 2430 J/g.

1)Generally in determining the molar mass of water evaporated we have that

-One mole (6.02 x 10. 23 molecules)

-Molar mass of water is 18.02 g/mol

Mathematically the mass of water is give as

   

  M=\frac{18.02}{6.02*10^-^2^6}

  M=3*10^-^2^3g

Therefore

  kinectic energy=2430J/g*3*10^-^2^3g

 kinectic energy=7.26*10^-^2^0J

b)Generally the evaporation speed V is given asV= \sqrt{\frac{K.E*2}{m} }

Mathematically derived from the equation

\frac{1}{2} mv^2 =K.E

To Give

V= \sqrt{\frac{K.E*2}{m} }

V= \sqrt{\frac{7.26*10^-^2^0J*2}{3*10^-^2^3g} }

V= 2.0m/s

c)Generally the equation for velocity   Vrms=\sqrt{\frac{3RT}{M} }

Therefore

Effective temperature T is given by

      T=\frac{\sqrt{v}*m}{R}

where

     T=\frac{\sqrt{2.0m/s}*6.02*10^-^2^6}{0.082057 L atm mol-1K-1}

     T=3.5*10^3K

4) The Molecules do not burn because of the presences of hydrogen bond in place

3 0
3 years ago
How do you calculate elastic potential energy
Nimfa-mama [501]
U=1/2kx2

This image sums it up
5 0
3 years ago
An ammeter is connected in series with a resistor of unknown resistance R and a DC power supply of known emf e. A student uses t
rosijanka [135]

Answer:

B:The actual power dissipated by the resistor is less than P because the ammeter had some resistance.

Explanation:

Here,power has been calculated using current I and total EMF \ε . So,P=EMF*current= ε I will represent total power dissipated in resistor and ammeter.

Now, this total power P has been dissipated in both resistor and ammeter. So, power dissipated in resistor must be less than P as some power is also dissipated in ammeter because it has non-zero resistance.

So, the answer is B:The actual power dissipated by the resistor is less than P because the ammeter had some resistance.

Note that option A,C and E are ruled out as they state power dissipated by resistor is greater than or equal to P which is false.

Also,option D is ruled out as ammeter is connected in series.

8 0
4 years ago
A meter stick moves parallel to its axis with speed of 0.96 c relative to you. What would you measure for the length of the stic
Fed [463]

Answer:

The length of the stick is 0.28 m.

The time the stick take to move is 0.97 ns.

Explanation:

Given that,

Relative speed of stick v= 0.96 c

Speed of light c= 2.99793\times10^{8}\ m/s

Proper length of stick = 1 m

We need to calculate the length of the stick

Using formula of length

\Delta l=\Delta l_{0}\sqrt{(1-\dfrac{v^2}{c^2})}

Put the value into the formula

\Delta l=1\sqrt{1-\dfrac{(0.96)^2c^2}{c^2}}

\Delta l=1\sqrt{1-(0.96)^2}

\Delta l=0.28\ m

We need to calculate the time the stick take to move

Using formula of time

t=\dfrac{\Delta l}{v}

Put the value into the formula

t=\dfrac{0.28}{0.96\times(2.99793\times10^{8})}

t=9.72\times10^{-10}\ sec

t=0.97\ ns

Hence, The length of the stick is 0.28 m.

The time the stick take to move is 0.97 ns.

7 0
3 years ago
an ice skater starts with a velocity 2.25 m/s in a 50.0 degree direction after 8.33s she is moving 4.65 m/s in a 120 degree dire
svetoff [14.1K]

Answer:

-0.032 m/s^2

Explanation:

To answer the question, we just need to consider the motion along the horizontal direction.

The component of the initial velocity of the ice skater along the x-direction is:

u_x = u cos \theta =(2.25)(cos 50^{\circ})=1.45 m/s

where u = 2.25 m/s is the initial velocity and 50^{\circ} is the angle.

The component of the final velocity of the ice skater along the x-direction is

v_x = u cos \theta =(4.65)(cos 120^{\circ})=-2.33 m/s

where u = 4.65 m/s is the final velocity and 120^{\circ} is the angle.

The acceleration along the x-direction is given by

a_x=\frac{v_x-u_x}{t}

where

t = 120 s is the time

Substituting,

a=\frac{-2.33-(1.45)}{120}=-0.032 m/s^2

7 0
4 years ago
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