Question

an ice skater starts with a velocity 2.25 m/s in a 50.0 degree direction after 8.33s she is moving 4.65 m/s in a 120 degree direction what is the x-component of her acceleration

Answer 1

Answer:

$-0.032 m/s^2$

Explanation:

To answer the question, we just need to consider the motion along the horizontal direction.

The component of the initial velocity of the ice skater along the x-direction is:

$u_x = u cos \theta =(2.25)(cos 50^{\circ})=1.45 m/s$

where u = 2.25 m/s is the initial velocity and $50^{\circ}$ is the angle.

The component of the final velocity of the ice skater along the x-direction is

$v_x = u cos \theta =(4.65)(cos 120^{\circ})=-2.33 m/s$

where u = 4.65 m/s is the final velocity and $120^{\circ}$ is the angle.

The acceleration along the x-direction is given by

$a_x=\frac{v_x-u_x}{t}$

where

t = 120 s is the time

Substituting,

$a=\frac{-2.33-(1.45)}{120}=-0.032 m/s^2$