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Phoenix [80]
3 years ago
7

Even though you are getting closer to the sun as you ascend into the toposphere, why does the temperature drop?

Physics
2 answers:
pishuonlain [190]3 years ago
4 0

Answer: The lower areas of the Atmosphere have a high temperature through the heats from the ground.

Explanation: High temperature experienced on the Earth surface is majorly caused by heats from the ground ( Earth crust).As a person ascend up to the Toposphere the temperature continues to reduce because because the heat from the ground is reduced as the heights increased.

It has been proven that as a person ascends into the Toposphere the amount of air and pressure reduces this will eventually lead to expansion of the gas particles which will then reduce the temperature.

Korvikt [17]3 years ago
3 0

Answer: The lower areas of the Atmosphere have a high temperature through the heats from the ground.

Explanation: High temperature experienced on the Earth surface is majorly caused by heats from the ground ( Earth crust).As a person ascend up to the Troposphere the temperature continues to reduce because because the heat from the ground is reduced as the heights increased.

It has been proven that as a person ascends into the Troposphere the amount of air and pressure reduces this will eventually lead to expansion of the gas particles which will then reduce the temperature.

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3 years ago
An electric motor does 900j of work for 8 hours. Calculate the power used​
nataly862011 [7]

Answer:

0.031 W

Explanation:

The power used is equal to the rate of work done:

P=\frac{W}{t}

where

P is the power

W is the work done

t is the time taken to do the work W

In this problem, we have:

W = 900 J is the work done by the motor

t = 8 h is the time taken

We have to convert the time into SI units; keeping in mind that

1 hour = 3600 s

We have

t=8\cdot 3600 =28,800 s

And therefore, the power used is

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3 years ago
An object is placed at 1.5 m from a convex lens with a focal length of 1.0 m.
AleksAgata [21]
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3 years ago
A 1300 kg car moving at 20 m/s and a 900 kg car moving at 15 m/s in precisely oppositedirections participate in a head-on crash.
miskamm [114]

Given

Car 1

m1 = 1300 kg

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m2 = 900 kg

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(Negative sign shows that direction of car 2 is opposite to car 1)

Procedure

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\begin{gathered} m_1v_1+m_2v_2=(m_1+m_2)v \\ v=\frac{m_1v_1+m_2v_2}{m_1+m_2} \\ v=\frac{1300\operatorname{kg}\cdot20m/s-900\operatorname{kg}\cdot15m/s}{1300\operatorname{kg}+900\operatorname{kg}} \\ v=5.681m/s \end{gathered}

Thus, we can conclude that the speed and direction of the cars after the impact is 5.68 m/s towards the first car.

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Setler79 [48]

Answer:A

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5 0
3 years ago
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