Answer: 2.49×10^-3 N/m
Explanation: The force per unit length that two wires exerts on each other is defined by the formula below
F/L = (u×i1×i2) / (2πr)
Where F/L = force per meter
u = permeability of free space = 1.256×10^-6 mkg/s^2A^2
i1 = current on first wire = 57A
i2 = current on second wire = 57 A
r = distance between both wires = 26cm = 0.26m
By substituting the parameters, we have that
Force per meter = (1.256×10^-6×57×57)/ 2×3.142 ×0.26
= 4080.744×10^-6/ 1.634
= 4.080×10^-3 / 1.634
= 2.49×10^-3 N/m
Rw/Ra = MA
18cm/2cm= MA
MA = 9
This means that Fi is 1/9 of the force applied to the axil. The distance travelled by Rw is 9 times more than Ri is that you move 9 times more when turning the wheel using Rw.
Put more simply
Rw/Ra = Fa/Fw
- Rw = Radius of the wheel
- Ra = Radius of the axil
- Fa = Force delivered on the axil
- Fw = Force delivered by the wheel
Answer:
12 Ohms
if all resistor are the same, use resistance=resistor * # of resistors.
Answer:
the pressure exerted on the turf when the player lands on his knee is 240,000 N/m².
Explanation:
Given;
combined weight of the players, F = 2400 N
measurement of the player's knee = 0.1 m by 0.1 m
The area of the player's knee is calculated as;
A = 0.1 m x 0.1 m = 0.01 m²
The pressure exerted on the turf when the player lands on his knee is calculated as;
P = F / A
P = (2400 N) / (0.01 m²)
P = 240,000 N/m²
Therefore, the pressure exerted on the turf when the player lands on his knee is 240,000 N/m².
Conduction, Convection, and Radiation