Explanation:
Initial speed of blood, u = 0
Final speed of the blood, v = 26 cm/s
(a) Displacement of the blood, d = 2 cm
Let a be its acceleration. It can be calculated using third equation of motion as :
(b) Let t is the time taken by the blood to reach its final speed. It can be calculated as :
<u></u>
t = 0.15 s
Hence, this is the required solution.
Answer:
In kinematics questions we need to separate the question into different parts if the acceleration changes. Here, there are three time intervals where acceleration is different.
1) a(t) = 96t. We can find the velocity function of the rocket by integrating the acceleration function. Then we can integrate again to find the position function.
'C' is the integration constant. We can find this constant by investigating the initial conditions.
We know that the rocket is initially at rest, so 'C' should be zero.
Again, the rocket started from ground zero, so C = 0.
We should conclude the first part by calculating the final position and final velocity of the rocket.
2) For the second part, the rocket is in free fall, so
The maximum height that the rocket reaches is when its velocity is zero.
So,
The maximum height is
The final positions for the part 2 is
3) With the parachute, the velocity is dropped from -276.4 to 16 in 5 s.
The rocket lands
The formula for potential energy is mass x height x gravitational force. Your mass is 5.3 kg and your height is 6.6 meters. The gravitational force on earth is 9.8 m/s. That means your answer is 5.3 x 6.6 x 9.8 and that equals 342.804