1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
BaLLatris [955]
3 years ago
8

1. A is a quadrilateral with exactly one pair of parallel sides.

Mathematics
2 answers:
strojnjashka [21]3 years ago
8 0

Answer:

So what’s the question?

Step-by-step explanation:

mr_godi [17]3 years ago
3 0
What is the question your trying to get the answer to?
You might be interested in
What is 9/16 more than 11/12
mixer [17]
11/12 is the greatest fraction
7 0
4 years ago
A jogger runs 6 miles per hour faster downhill than uphill. If the jogger can run 5 miles downhill in the same time that it take
muminat

Answer:

The speed of jogger in uphills is 4 mile per hour  

And  The speed of jogger in downhills is 10 mile per hour

Step-by-step explanation:

Given as :

The distance cover by jogger in downhill (Dd) = 5 miles

The distance cover by jogger in uphill     (Du)  = 2 miles

The time taken by jogger in downhill       (Td)  = T  hour

The time taken by jogger in uphill            (Tu)  = T hour

Let The speed of jogger in uphills            (Su)  = x mph

So ,The speed of jogger in downhills      (Sd)  =( x + 6 ) mph

∵, Time = \frac{Distance}{Speed}

So, Tu = \frac{Du}{Su}

Or, T = \frac{2}{x}   h

And Td = \frac{Dd}{Sd}

Or,   T = \frac{5}{(x + 6)}  h

∵  Time duration of both is same

∴  \frac{2}{x} = \frac{5}{(x + 6)}

Or,  2 × (x + 6) = 5x

Or,  2x + 12 = 5x

So,    12 = 3x

∴       x = \frac{12}{3} = 4 mph

And  x + 6 = 4 + 6 = 10 mph

Hence The speed of jogger in uphills is 4 mile per hour  

And      The speed of jogger in downhills is 10 mile per hour   Answer

5 0
3 years ago
An observer on the ground is x meters from the base of the launch pad of a rocket, which is at the same level as the observer. A
Flauer [41]
To illustrate the problem, refer to the following diagram, made with the ever-helpful notepad application:

  |\  |  \  |    \h|      \  |        \  |          \  |_____q\      x

Pretending as if that is a wonderfully-drawn triangle, we are given the distance x of the observer from the launch pad. The angle q is also stated, and is located in the diagram as shown. To look for the distance h of the tip of the rocket to the ground, we consider the following trigonometry function:

tan q = h/x

Since we are solving for h, we multiply both sides with x, giving us:

h = x * tan q

Among the choices, the correct answer is C.
8 0
3 years ago
Find ''m'' and ''c'' of 3-2x+y=0 by comparing with y=mx+c
shusha [124]

Answer:

m=-2 c=3

Step-by-step explanation:

y=mx+c

rearrange

-mx-c+y=0

original

y=2x-3

4 0
3 years ago
Felicia's mother is four times as old as Felicia in 16 years her mother will be twice or age how old is Felisha now
trapecia [35]
Mother  = M
Felicia = F
{M = 4F
16 + M = 2(F + 16)
 {M - 2F = 16

4F - 2F = 16
2F = 16
F = 8 age
M = 4*8 = 32 age
3 0
3 years ago
Other questions:
  • He nine ring wraiths want to fly from barad-dur to rivendell. rivendell is directly north of barad-dur. the dark tower reports t
    8·1 answer
  • 10. Using Base 10 blocks, show & explain how to divide 35 (3 longs and 5 units) by 5. (DRAW
    8·1 answer
  • Which will result in a difference of squares?
    10·2 answers
  • In Exercise,find the horizontal asymptote of the graph of the function.<br> f(x) = 8x^3+2/2x^3+x
    7·1 answer
  • Brynne has 13 books she has 8 more books than games how many game does Brynne have
    11·2 answers
  • Y=3x-1 substitute -3 for x
    5·1 answer
  • Find the measure of the missing angles.
    6·1 answer
  • If m(x) = x2 + 3 and n(x) = 5x + 9, which expression is equivalent to (mn)(x)?
    13·2 answers
  • IF U UNDERSTAND THIS PLS ANSWER WITH NO LINK!!!​
    13·1 answer
  • Find the percent of change. 32 to 28
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!