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2 years ago

Which types of atomic orbitals of the central atom mix to form hybrid orbitals in: (c) PF₅;

Chemistry

1 answer:

zloy xaker [14]2 years ago

5 0

The atomic orbitals of the central atom mix to form hybrid orbitals are one s and three p.

<h3>Which atomic orbitals are used to form hybrid orbitals?</h3>

Pauling supposed that in the presence of four hydrogen atoms, the s and p orbitals form four equivalent combinations which he called hybrid orbitals.

<h3>How many bonds does PF5?</h3>

Phosphorus pentafluoride has 5 regions of electron density around the central phosphorus atom (5 bonds, no lone pairs).

The resulting shape is a trigonal bipyramidal in which three fluorine atoms occupy equatorial and two occupy axial positions.

Learn more about PF5 here:

<h3>brainly.com/question/1565926</h3><h3 /><h3>#SPJ4</h3>

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Write the formula for the complex ion formed by the metal ion Cr3+ and six NO2- ions as ligands. Decide whether the complex coul

Dmitrij [34]

Answer:The metal complex formed would have the following formula [Cr(NO₂)₆]³⁻. The complex has a net negative charge and hence it can only be isolated as a salt with a positive cation so the formed complex could be isolated as potassium salt. The formula for salt would be K₃[Cr(NO₂)₆].

Explanation:

The metal ion given to us is Cr³⁺ (Chromium) in +3 oxidation state.

The electronic configuration for the metal ion is [Ar]3d³ so there are vacant 3d metal orbitals which are available and hence 6 NO₂⁻ ligands can easily attack the metal center and form a metal complex.

The charge on the overall complex can be calculated using the oxidation states of metal and ligand which is provided.

The (chromium ) Cr³⁺ metal has +3 charge and 6 NO₂⁻ (nitro) ligands have -6 charge and since the ligands will be providing a total of 6 - (negative) charge and hence only 3- (negative ) charge can be neutralized so a net 3- negative charge would be present on the overall complex which is basically present at the metal center :

charge on the complex=+3-6=-3

Let X be the Oxidation state of Cr in complex =[Cr(NO₂)₆]³⁻

X-6=-3

X=-3+6

X=+3

so our calculated oxidation state of Cr is +3 which matches with the provided in question.

As we can see that the overall metal complex has a net negative charge and hence and only positively charged cations can form a salt with this metal complex and hence only potassium K⁺ ions can form salt with the metal complex.

since overall charge present on the metal complex is -3 so 3 K⁺ ion would be needed to neutralize it and hence the formula of the metal salt would be K₃[Cr(NO₂)₆].

3 0

3 years ago

An element with 5 valence electrons would be a

agasfer [191]

Answer:

ask you subject teacher

Explanation:

4 0

3 years ago

To what volume (in mL) would you need to dilute 25.0mL of a 1.45 m solution of Kcl to make a 0.0245m solution of KCl

dezoksy [38]

Answer:

The answer is

Explanation:

In order to calculate the volume needed we use the formula

$V_2 = \frac{C_1V_1}{C_2}$

where

C1 is the concentration of the stock solution

V1 is the volume of the stock solution

C2 is the concentration of the diluted solution

V2 is the volume of thevdiluted solution

From the question

C1 = 1.45 M

V1 = 25 mL

C2 = 0.0245 M

So we have

$V_2 = \frac{1.45 \times 25}{0.0245} = \frac{36.25}{0.0245} \\ = 1479.59...$

We have the final answer as

Hope this helps you

4 0

3 years ago

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jenyasd209 [6]

Answer:

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6 0

4 years ago

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Balance the following chemical questions

Gre4nikov [31]

Answer:

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3. C2H6O+<u>3</u>O2--><u>2</u>CO2+<u>3</u>H2O

4.<u>2</u>AgI+Na2S-->Ag2S+<u>2</u>NaI

8 0

3 years ago