The volume of air in a person's lungs is about 615 ml, at a pressure of 760 mm Hg. Inhalation occurs when the pressure in the lungs drops to 752 mm Hg. To what volume do the lungs expand?
Answer:
621.5mL
Explanation:
Given parameters:
Initial volume = 615mL
Initial pressure = 760mmHg
Final pressure = 752mmHg
Unknown;
Final volume = ?
Solution:
To solve this problem, we simply apply Boyle's law.
"the volume of a fixed mass of a gas varies inversely as the pressure changes if the temperature is constant".
Mathematically;
P₁V₁ = P₂V₂
P and V are the pressure
1 and 2 are the initial and final states
Now insert the parameters and start;
760 x 615 = 752 x V₂
V₂ = 621.5mL
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Answer:Hence, the bond length in HCl is 125 pm.
Explanation:
Bond length : It is an average distance between the nuclei of two bonded atoms in a molecule.
Also given that bond length is the distance between the centers of two bonded atoms. on the potential energy curve, the bond length is the inter-nuclear distance between the two atoms when the potential energy of the system reaches its lowest value. Beyond this if atoms come closer to each other then their will be repulsion between them.
So, the bond length between the Hydrogen and Chlorine atom in HCl molecule is :
Hence, the bond length in HCl is 125 pm.
Answer: Kc= 4.653
Explanation:
From The equation of reaction
CO(g)+2H2(g)⇌CH3OH(g)
From the question
[CH3OH] =0.0679 moles
[CO]= 0.160moles
[H2]= 0.302
Kc = [CH3OH]/[CO] [H2]^2
Kc=[0.069]/[0.16]×[0.302]^2
Kc= 4.653
